anonymous
  • anonymous
Need Help! Find the limit of the limit below
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
|dw:1439230879897:dw|
hartnn
  • hartnn
when v->4+ means v is very very near to 4, but greater than 4. agreed?
anonymous
  • anonymous
Yep

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hartnn
  • hartnn
so, 4-v will be positive or negative?
anonymous
  • anonymous
negative?
hartnn
  • hartnn
thats right :) and since the denominator is having a modulus, it will be positive only. so our final answer will be negative!
anonymous
  • anonymous
|dw:1439231347038:dw|
anonymous
  • anonymous
I understand by writing things out..
hartnn
  • hartnn
i meant |4-v| is always positive and 4-v is negative
anonymous
  • anonymous
So how would I solve it?
hartnn
  • hartnn
4-v from numerator and denominator would cancel out, so the answer would be either +1 or -1 the numerator is negative, and denominator is positive, so the overall answer is negative, that is -1.
anonymous
  • anonymous
Are you sure it's that simple?
hartnn
  • hartnn
yep!
anonymous
  • anonymous
|dw:1439231746924:dw|Is that how the work would look like?
hartnn
  • hartnn
ok, lets make some steps, since v is very near to 4, but greater than 4, lets take v = 4 + \(\delta \) when \(v \to 4^+\), \(\delta \to 0\) |dw:1439231931131:dw| try to simplify that ^^
anonymous
  • anonymous
1?
hartnn
  • hartnn
the numerator simplifies to \(-\delta\) and the denominator simplifies to \(|-\delta | = \delta\) isn't it ?
hartnn
  • hartnn
|dw:1439232227653:dw|
anonymous
  • anonymous
I see it now! thanks for the clear work
hartnn
  • hartnn
welcome ^_^

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