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anonymous
 one year ago
Need Help! Find the limit of the limit below
anonymous
 one year ago
Need Help! Find the limit of the limit below

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439230879897:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1when v>4+ means v is very very near to 4, but greater than 4. agreed?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, 4v will be positive or negative?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1thats right :) and since the denominator is having a modulus, it will be positive only. so our final answer will be negative!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439231347038:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand by writing things out..

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i meant 4v is always positive and 4v is negative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how would I solve it?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.14v from numerator and denominator would cancel out, so the answer would be either +1 or 1 the numerator is negative, and denominator is positive, so the overall answer is negative, that is 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you sure it's that simple?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439231746924:dwIs that how the work would look like?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, lets make some steps, since v is very near to 4, but greater than 4, lets take v = 4 + \(\delta \) when \(v \to 4^+\), \(\delta \to 0\) dw:1439231931131:dw try to simplify that ^^

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1the numerator simplifies to \(\delta\) and the denominator simplifies to \(\delta  = \delta\) isn't it ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see it now! thanks for the clear work
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