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anonymous
 one year ago
Graphing please
anonymous
 one year ago
Graphing please

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439231312962:dw Will medal!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439231406656:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2first graph: we have to consider these 2 cases: 1) \[x  2 \geqslant 0\] and: 2)\[x  2 < 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright. But for this hw assignmnet, I dont have to show work, i just have to graph it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, is there a website where I can go on to type it in?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I understand, nevertheless I can not give you the graph, since I have to guide you to your solution

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2in the first case your function is: \[\Large \begin{gathered} y =  \frac{1}{3}\left( {x  2} \right) + 2 =  \frac{x}{3} + \frac{2}{3} + 2 \hfill \\ \hfill \\ y =  \frac{x}{3} + \frac{8}{3} \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, then i would just plug in some points to get the answer

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2in thesecond case, the equation of your function is: \[\Large \begin{gathered} y =  \frac{1}{3} \cdot  \left( {x  2} \right) + 2 = \frac{x}{3}  \frac{2}{3} + 2 \hfill \\ \hfill \\ y = \frac{x}{3} + \frac{4}{3} \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! for example, I consider the first function: \[\Large y =  \frac{x}{3} + \frac{8}{3}\] if x=0, then y=8/3, so that line passes at (0,8/3) whereas if y=0, then x=8, so that line passes at point (8,0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! Okay, thank you:) I understand it now

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439232238778:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2in the second case, I consider this function: \[\Large y = \frac{x}{3} + \frac{4}{3}\] now, if x=0, then y= 4/3, so that line passes at (0, 4/3) whereas if y=0, then x=4, so that line passes at (4, 0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok and then i can just graph it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much for all ur help!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439232482291:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2similarly for second graph

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2for second graph, you have to consider these 2 subsequent cases: \[\Large \begin{gathered} x + 3 \geqslant 0 \hfill \\ x  3 < 0 \hfill \\ \end{gathered} \] and repeat the procedure above
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