anonymous
  • anonymous
f(x)=x^2+3x-4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
find the domain,range, axis of symetry, and vertex
anonymous
  • anonymous
@Hero
Hero
  • Hero
@pooja195, help her

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anonymous
  • anonymous
:)
pooja195
  • pooja195
Have you started this yet? If so what do you have so far? :)
anonymous
  • anonymous
No, I tried to but it didn't really make sense. I graphed it though by plugging in points
pooja195
  • pooja195
Thats fine Starting with all real numbers, the domain is the largest possible set of x values that has a meaningful y value. The largest possible set of x values is all the real numbers, since each real number has a meaningful output , there is no division by zero or square root of a negative number.
anonymous
  • anonymous
okay so the domain would be all real numbers?
pooja195
  • pooja195
yes :)
pooja195
  • pooja195
Wanna try out range?
anonymous
  • anonymous
sure
pooja195
  • pooja195
For range there is no simple formula. You have to look at the graph and find the y values which are 'hit'
anonymous
  • anonymous
y<=4?
pooja195
  • pooja195
Look at this https://www.desmos.com/calculator/9zbczplemb
pooja195
  • pooja195
Range would be the green line
pooja195
  • pooja195
if you shine a flashlight horizontally , the range is the shadow
anonymous
  • anonymous
so, y<-3/2??
pooja195
  • pooja195
thats the axis of symmetry
anonymous
  • anonymous
ok, so then what would the range be? Sorry, I dont understand this part
pooja195
  • pooja195
The range would be y>= -25/4 because the range is the y values of the ordered pairs of your function
anonymous
  • anonymous
oh okay! So now all we need is the vertex which is -1.5,-6.25?
pooja195
  • pooja195
Thats correct good job :)
anonymous
  • anonymous
Thanks for your help:))
pooja195
  • pooja195
\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e\color{#24ff00}~\color{#00ff00}t\color{#00ff49}o\color{#00ff92}~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\)\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Large\bf\color{Lime}{Please,\ don't\ hesitate\ to\ ask\ questions!}\)\(\Large\bf\color{magenta}{We're\ here\ to\ help!}\Large\color{magenta}{\ddot\smile}\)
anonymous
  • anonymous
Lol! Aww! That's so sweet<3!!!! Thanks:D
pooja195
  • pooja195
:3 <3
anonymous
  • anonymous
ty you too, hero:)
pooja195
  • pooja195
@ChloeSiouz hold up theres a mistake
anonymous
  • anonymous
Ok:)
pooja195
  • pooja195
range is y>-4 it means you can't get value less than -4 by putting any value of x
anonymous
  • anonymous
Alright, is the axis of symmetry still the same though?
anonymous
  • anonymous
so, is everything else okay?
pooja195
  • pooja195
It remains the same. Everything else looks fine.
anonymous
  • anonymous
cool:)! Glad you caught that hhaaha:)
pooja195
  • pooja195
:)

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