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itsmichelle29
 one year ago
If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?
itsmichelle29
 one year ago
If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1draw a triangle, like this dw:1439233810971:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1there is a picture of an angle where the sine is \(\frac{1}{4}\) since the "opposite over adjacent" is \(\frac{1}{4}\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i meant "opposite over hypotenuse"

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1what you need is the adjacent side, which you find via pythagoras let me know when you get it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1use pythagoras \[a^2+b^2=c^2\\ x^2+1^2=4^2\\ x^2+1=16\\ x^2=161=15\] so \[x=\sqrt{15}\]

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0okay is the answe root15 /4

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you want the tangent right? not the cosine

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0can u help me with like two more plz

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1and i will be happy to help with two more

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0What are the period and phase shift for f(x) = −4 tan(x − π)?

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0i think its pi and pi

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1period of tangent is \(\pi\) so yeah

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1phase shift is \(\pi\) as well you are right

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0Use the graph below to answer the question that follows: cosine graph with points at 0, negative 1 and pi over 2, 3 and pi, negative 1 What are the amplitude, period, and midline of the function? Amplitude: 8; period: π; midline: y = 1 Amplitude: 8; period: 2π; midline: y = 5 Amplitude: 4; period: 2π; midline: y = 5 Amplitude: 2; period: π; midline: y = 1

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1really need the graph for this one

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok much better got a guess?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1only need to look at the amplitude to pick from your choices

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0Amplitude: 8; period: π; midline: y = 1 Amplitude: 8; period: 2π; midline: y = 5 Amplitude: 4; period: 2π; midline: y = 5 Amplitude: 2; period: π; midline: y = 1

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0well i thought it was 1 but thats not a chose

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1from 1 to 3, that is from the lowest point to the highest, is a distance of 4 units the amplitude is half of that i.e. 2

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1also you can see that the period is \(\pi\) since it goes up, and back down to 1 from 0 to \(\pi\)

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0Amplitude: 2; period: π; midline: y = 1 is that the answer

itsmichelle29
 one year ago
Best ResponseYou've already chosen the best response.0omg ur amazing thanks

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lol thanks\[\color\magenta\heartsuit\]
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