anonymous
  • anonymous
YAS
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@welshfella @Hero @acxbox22 @LegendarySadist @prowrestler @Zale101 @xavierbo2 @campbell_st @vera_ewing @bubbleslove1234
anonymous
  • anonymous
@ikram002p @IrishBoy123 @imqwerty @AliceCullen @sammixboo
anonymous
  • anonymous
@nincompoop @nuccioreggie

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campbell_st
  • campbell_st
ok, what is a simply linear equation...?
anonymous
  • anonymous
y=5x+3
campbell_st
  • campbell_st
next, what is a simple quadratic equation...?
anonymous
  • anonymous
16x^2+4x+2
anonymous
  • anonymous
what do I do now?
anonymous
  • anonymous
hello? @campbell_st
campbell_st
  • campbell_st
well I wouldn't have considered the 2 equations simple... the quadratic is positive definite.... which means it won't cut the x-axis by anyway, you have 2 equations... next step is to solve them simultaneously y = 5x + 3 y = 16x^2 + 4x + 2 so to solve them just equate them 5x + 3 = 16x^2 + 4x + 2 then solve for x. but you have chosen 2 difficult equations... I've attached a file, its a graph of your 2 equations
1 Attachment
campbell_st
  • campbell_st
so you may want to rethink your equations.
anonymous
  • anonymous
i just made up 2 random equations I don't know what equations to think of
campbell_st
  • campbell_st
ok... so start with simple you linear equation is almost ok change the y-intercept to 6 so use y = 5x + 6 now a really simply quadratic is \[y = x^2\] So equating them you get \[5x + 6 = x^2\] or \[x^2 - 5x - 6 = 0\] this is a quadratic equation that can be solved by factoring... so that is what you need to do, solve for x, when you get the 2 answers, substitute the x values into either equation to find the matching y values... so you will have 2 point of intersection... if you have to graph the curves 1 use a table of values that includes both x values or just just some graphing software line https://www.desmos.com/calculator
anonymous
  • anonymous
thank you! @campbell_st

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