A bowl contains 4 yellow marbles and 3 red marbles. Eric randomly draws 3 marbles from the bowl. He replaces each marble after it is drawn. What is the probability that he draws 1 yellow marble and 2 red marbles?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Welcome to OpenStudy!

- anonymous

How many marbles are there in total in the bowl?

- anonymous

7

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Right. When Eric draws the first marble, what's the probability that it will be yellow?

- anonymous

Hello?

- anonymous

4/7?

- anonymous

Correct. Very good. Now Eric puts the marble back in the bowl so there's still 4 yellow and 3 red marbles in the bowl. So it's just like we're back at the beginning again. Now, Eric draws another marble. What is the probability it will be red?

- anonymous

Hello?

- anonymous

3/7

- anonymous

Very good. Now Eric puts that marble back in the bowl and it's just like we're back at the beginning. Eric draws for the third time. What's the probability it will be red?

- anonymous

3/7

- anonymous

Good. In probability, these events are called independent events because one draw has no effect on the next one (Eric puts the marble back in the bowl). The total probability of drawing 1 yellow and 2 red is the product of the three individual probabilities, i.e.\[P = \frac{ 4 }{ 7 } \times \frac{ 3 }{ 7 } \times \frac{ 3 }{ 7 }\]What do you get?

- anonymous

36/343

Looking for something else?

Not the answer you are looking for? Search for more explanations.