How do you solve for this equation?

- Ineedhelpfast12

How do you solve for this equation?

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- Ineedhelpfast12

|dw:1439238581334:dw|

- anonymous

does that say\[\frac{ x }{ 3 }+\frac{ 2 }{ 5 }\]?

- Ineedhelpfast12

yes

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## More answers

- anonymous

is that all of the equation?

- Ineedhelpfast12

yes

- anonymous

I don't think you can solve, but rather just simplify

- Ineedhelpfast12

how though

- anonymous

does it say if x equals anything?

- Ineedhelpfast12

11\[\frac{ 11 }{ 15}x\]?

- Ineedhelpfast12

no it just says solve for x

- anonymous

interesting, I'll tag someone @ccieux

- phi

***How do you solve for this equation? ***
an equation *always* has an = sign
where is your equal sign?

- Ineedhelpfast12

Fine how do you solve the PROBLEM?

- Ineedhelpfast12

@Nnesha help please

- jdoe0001

EQUATions "equate" to something
so... you don't really have to "solve" anything per se

- jdoe0001

as phi said, there's no = sign

- Ineedhelpfast12

anybody out there speak english? I do not understand what jdoe0001 means

- anonymous

looks to me like a cross multiplication problem

- zzr0ck3r

@jdoe0001 is saying that in order to solve for \(x\) we need an equals sign. You just gave an expression, not an equation.

- Ineedhelpfast12

but it is an addition problem

- jdoe0001

hmmm

- Ineedhelpfast12

I am not trying to solve for x. I just need to simplify x/3+2/5

- anonymous

cross multiply then add, but i get what you guys are saying about their not being an equals sign =/

- Ineedhelpfast12

This is only Algebra 1 people. What does x6 stand for?

- jdoe0001

\(\bf \cfrac{x}{3}+\cfrac{2}{5}\implies \cfrac{}{LCD=15}\implies \cfrac{(15\div 3)x+(15\div5)2}{15}\)

- zzr0ck3r

\[\dfrac{x}{3}+\dfrac{2}{5}=\dfrac{5x}{5*3}+\dfrac{2*3}{5*3}=\dfrac{5x+6}{15}\]

- Ineedhelpfast12

How about another question?

- zzr0ck3r

hopefully it makes sense :)

- Ineedhelpfast12

|dw:1439250294613:dw|

- Ineedhelpfast12

that is a t

- zzr0ck3r

do you see how we simplified before?

- Ineedhelpfast12

no

- zzr0ck3r

\(\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+cb}{bd}\)

- Ineedhelpfast12

ok

- zzr0ck3r

for you \[a=x, b=y, c=2, d=t\]

- Ineedhelpfast12

so is it|dw:1439250477962:dw|

- zzr0ck3r

But you must realize we are not solving anything here, we are just simplifying.

- zzr0ck3r

yep

- Ineedhelpfast12

ok

- Ineedhelpfast12

a couple more

- zzr0ck3r

do the same thing...

- zzr0ck3r

I will tell you if you have the right answer

- Ineedhelpfast12

|dw:1439250550081:dw|

- zzr0ck3r

what would be the lcd?

- Ineedhelpfast12

80

- zzr0ck3r

40

- zzr0ck3r

sec

- Ineedhelpfast12

oh ya

- zzr0ck3r

\[\frac{2t}{8xy}+\dfrac{4tx}{10y}\]
We want the denominator to be the same, lcm(8,10)=40
and we are missing an x on the right side
\[\dfrac{5*2*t}{4*x*y}+\dfrac{4*4*t*x}{4*10*y*x}\]

- Ineedhelpfast12

me no get it

- anonymous

did yall solve it?

- Ineedhelpfast12

no we did not

- Ineedhelpfast12

hey @amsalvad canst thou help?

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