## Ineedhelpfast12 one year ago How do you solve for this equation?

1. Ineedhelpfast12

|dw:1439238581334:dw|

2. anonymous

does that say$\frac{ x }{ 3 }+\frac{ 2 }{ 5 }$?

3. Ineedhelpfast12

yes

4. anonymous

is that all of the equation?

5. Ineedhelpfast12

yes

6. anonymous

I don't think you can solve, but rather just simplify

7. Ineedhelpfast12

how though

8. anonymous

does it say if x equals anything?

9. Ineedhelpfast12

11$\frac{ 11 }{ 15}x$?

10. Ineedhelpfast12

no it just says solve for x

11. anonymous

interesting, I'll tag someone @ccieux

12. phi

***How do you solve for this equation? *** an equation *always* has an = sign where is your equal sign?

13. Ineedhelpfast12

Fine how do you solve the PROBLEM?

14. Ineedhelpfast12

15. anonymous

EQUATions "equate" to something so... you don't really have to "solve" anything per se

16. anonymous

as phi said, there's no = sign

17. Ineedhelpfast12

anybody out there speak english? I do not understand what jdoe0001 means

18. anonymous

looks to me like a cross multiplication problem

19. zzr0ck3r

@jdoe0001 is saying that in order to solve for $$x$$ we need an equals sign. You just gave an expression, not an equation.

20. Ineedhelpfast12

but it is an addition problem

21. anonymous

hmmm

22. Ineedhelpfast12

I am not trying to solve for x. I just need to simplify x/3+2/5

23. anonymous

cross multiply then add, but i get what you guys are saying about their not being an equals sign =/

24. Ineedhelpfast12

This is only Algebra 1 people. What does x6 stand for?

25. anonymous

$$\bf \cfrac{x}{3}+\cfrac{2}{5}\implies \cfrac{}{LCD=15}\implies \cfrac{(15\div 3)x+(15\div5)2}{15}$$

26. zzr0ck3r

$\dfrac{x}{3}+\dfrac{2}{5}=\dfrac{5x}{5*3}+\dfrac{2*3}{5*3}=\dfrac{5x+6}{15}$

27. Ineedhelpfast12

How about another question?

28. zzr0ck3r

hopefully it makes sense :)

29. Ineedhelpfast12

|dw:1439250294613:dw|

30. Ineedhelpfast12

that is a t

31. zzr0ck3r

do you see how we simplified before?

32. Ineedhelpfast12

no

33. zzr0ck3r

$$\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+cb}{bd}$$

34. Ineedhelpfast12

ok

35. zzr0ck3r

for you $a=x, b=y, c=2, d=t$

36. Ineedhelpfast12

so is it|dw:1439250477962:dw|

37. zzr0ck3r

But you must realize we are not solving anything here, we are just simplifying.

38. zzr0ck3r

yep

39. Ineedhelpfast12

ok

40. Ineedhelpfast12

a couple more

41. zzr0ck3r

do the same thing...

42. zzr0ck3r

I will tell you if you have the right answer

43. Ineedhelpfast12

|dw:1439250550081:dw|

44. zzr0ck3r

what would be the lcd?

45. Ineedhelpfast12

80

46. zzr0ck3r

40

47. zzr0ck3r

sec

48. Ineedhelpfast12

oh ya

49. zzr0ck3r

$\frac{2t}{8xy}+\dfrac{4tx}{10y}$ We want the denominator to be the same, lcm(8,10)=40 and we are missing an x on the right side $\dfrac{5*2*t}{4*x*y}+\dfrac{4*4*t*x}{4*10*y*x}$

50. Ineedhelpfast12

me no get it

51. anonymous

did yall solve it?

52. Ineedhelpfast12

no we did not

53. Ineedhelpfast12

hey @amsalvad canst thou help?