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anonymous

  • one year ago

I cant seem to figure this out help please :) What is the simplified form of 2 over x squared plus x minus 1 over x ?

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  1. anonymous
    • one year ago
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    \[\frac{ 2 }{ x^2+x }-\frac{ 1 }{ x }\]

  2. anonymous
    • one year ago
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    @mathstudent55 @MTALHAHASSAN2 @markaskingalexandria1 @animalfan1 @abs202 @Summersnow8 @RedNeckOutLaw

  3. MTALHAHASSAN2
    • one year ago
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    |dw:1439243455162:dw|

  4. MTALHAHASSAN2
    • one year ago
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    |dw:1439243547714:dw|

  5. MTALHAHASSAN2
    • one year ago
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    |dw:1439243586590:dw|

  6. MTALHAHASSAN2
    • one year ago
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    |dw:1439243628166:dw|

  7. mathstudent55
    • one year ago
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    The first step is to factor the left denominator. Can you do that?

  8. anonymous
    • one year ago
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    that's not one of the answers want me too post them?

  9. MTALHAHASSAN2
    • one year ago
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    @mathstudent55 is my answer right

  10. mathstudent55
    • one year ago
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    No.

  11. mathstudent55
    • one year ago
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    Once again, first, factor the left denominator.

  12. MTALHAHASSAN2
    • one year ago
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    how is it wrong?

  13. anonymous
    • one year ago
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    x minus 1 over the quantity x times x plus 1 1 minus x over the quantity x times x plus 1 3 minus x over the quantity x times x minus 1 x plus 2 over the quantity x times x minus 1

  14. anonymous
    • one year ago
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    oh so \[\frac{ 2 }{ x(x+1)}\]?

  15. mathstudent55
    • one year ago
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    This problem is a subtraction of fractions. We need a common denominator. The way to find a common denominator is to first factor all denomiators. \(\Large \dfrac{ 2 }{ x^2+x }-\dfrac{ 1 }{ x }\) Factor the left denominator. Correct. \(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{ 1 }{ x }\)

  16. mathstudent55
    • one year ago
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    Now you need to find the LCD of x(x + 1) and x.

  17. anonymous
    • one year ago
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    so x(x+1) is the lcd so multiply 1/x by x+1?

  18. mathstudent55
    • one year ago
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    Correct. Multiply 1/x by (x + 1)/(x + 1) \(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{ 1 }{ x } \times \dfrac{x + 1}{x + 1} \)

  19. anonymous
    • one year ago
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    now what

  20. mathstudent55
    • one year ago
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    \(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{x + 1}{x(x + 1)} \)

  21. mathstudent55
    • one year ago
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    Now do the actual subtraction. Write a new fraction with the common denominator, and subtract the numerators. Remember to enclose the second numerator in parentheses.

  22. MTALHAHASSAN2
    • one year ago
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    @mathstudent55 huh i goted

  23. anonymous
    • one year ago
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    x-1/x(x+1)?

  24. MTALHAHASSAN2
    • one year ago
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    so first you have to factor that x square

  25. mathstudent55
    • one year ago
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    \(\Large =\dfrac{ 2 - (x + 1)}{ x(x+1) } \) \(\Large =\dfrac{ 2 - x - 1}{ x(x+1) } \) \(\Large =\dfrac{ 1 - x}{ x(x+1) } \)

  26. mathstudent55
    • one year ago
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    Numerator is either 1 - x or -x + 1, not x - 1

  27. anonymous
    • one year ago
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    Sweet! That's one of the answers! THANK YOU I GET IT :)!!

  28. mathstudent55
    • one year ago
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    The first step was factoring x^2 + x

  29. mathstudent55
    • one year ago
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    Great. You're welcome.

  30. MTALHAHASSAN2
    • one year ago
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    @mathstudent55 nice work!!

  31. mathstudent55
    • one year ago
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    Thanks.

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