anonymous
  • anonymous
I cant seem to figure this out help please :) What is the simplified form of 2 over x squared plus x minus 1 over x ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\frac{ 2 }{ x^2+x }-\frac{ 1 }{ x }\]
anonymous
  • anonymous
@mathstudent55 @MTALHAHASSAN2 @markaskingalexandria1 @animalfan1 @abs202 @Summersnow8 @RedNeckOutLaw
MTALHAHASSAN2
  • MTALHAHASSAN2
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MTALHAHASSAN2
  • MTALHAHASSAN2
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MTALHAHASSAN2
  • MTALHAHASSAN2
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MTALHAHASSAN2
  • MTALHAHASSAN2
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mathstudent55
  • mathstudent55
The first step is to factor the left denominator. Can you do that?
anonymous
  • anonymous
that's not one of the answers want me too post them?
MTALHAHASSAN2
  • MTALHAHASSAN2
@mathstudent55 is my answer right
mathstudent55
  • mathstudent55
No.
mathstudent55
  • mathstudent55
Once again, first, factor the left denominator.
MTALHAHASSAN2
  • MTALHAHASSAN2
how is it wrong?
anonymous
  • anonymous
x minus 1 over the quantity x times x plus 1 1 minus x over the quantity x times x plus 1 3 minus x over the quantity x times x minus 1 x plus 2 over the quantity x times x minus 1
anonymous
  • anonymous
oh so \[\frac{ 2 }{ x(x+1)}\]?
mathstudent55
  • mathstudent55
This problem is a subtraction of fractions. We need a common denominator. The way to find a common denominator is to first factor all denomiators. \(\Large \dfrac{ 2 }{ x^2+x }-\dfrac{ 1 }{ x }\) Factor the left denominator. Correct. \(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{ 1 }{ x }\)
mathstudent55
  • mathstudent55
Now you need to find the LCD of x(x + 1) and x.
anonymous
  • anonymous
so x(x+1) is the lcd so multiply 1/x by x+1?
mathstudent55
  • mathstudent55
Correct. Multiply 1/x by (x + 1)/(x + 1) \(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{ 1 }{ x } \times \dfrac{x + 1}{x + 1} \)
anonymous
  • anonymous
now what
mathstudent55
  • mathstudent55
\(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{x + 1}{x(x + 1)} \)
mathstudent55
  • mathstudent55
Now do the actual subtraction. Write a new fraction with the common denominator, and subtract the numerators. Remember to enclose the second numerator in parentheses.
MTALHAHASSAN2
  • MTALHAHASSAN2
@mathstudent55 huh i goted
anonymous
  • anonymous
x-1/x(x+1)?
MTALHAHASSAN2
  • MTALHAHASSAN2
so first you have to factor that x square
mathstudent55
  • mathstudent55
\(\Large =\dfrac{ 2 - (x + 1)}{ x(x+1) } \) \(\Large =\dfrac{ 2 - x - 1}{ x(x+1) } \) \(\Large =\dfrac{ 1 - x}{ x(x+1) } \)
mathstudent55
  • mathstudent55
Numerator is either 1 - x or -x + 1, not x - 1
anonymous
  • anonymous
Sweet! That's one of the answers! THANK YOU I GET IT :)!!
mathstudent55
  • mathstudent55
The first step was factoring x^2 + x
mathstudent55
  • mathstudent55
Great. You're welcome.
MTALHAHASSAN2
  • MTALHAHASSAN2
@mathstudent55 nice work!!
mathstudent55
  • mathstudent55
Thanks.

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