I cant seem to figure this out help please :) What is the simplified form of 2 over x squared plus x minus 1 over x ?

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I cant seem to figure this out help please :) What is the simplified form of 2 over x squared plus x minus 1 over x ?

Mathematics
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\[\frac{ 2 }{ x^2+x }-\frac{ 1 }{ x }\]
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The first step is to factor the left denominator. Can you do that?
that's not one of the answers want me too post them?
@mathstudent55 is my answer right
No.
Once again, first, factor the left denominator.
how is it wrong?
x minus 1 over the quantity x times x plus 1 1 minus x over the quantity x times x plus 1 3 minus x over the quantity x times x minus 1 x plus 2 over the quantity x times x minus 1
oh so \[\frac{ 2 }{ x(x+1)}\]?
This problem is a subtraction of fractions. We need a common denominator. The way to find a common denominator is to first factor all denomiators. \(\Large \dfrac{ 2 }{ x^2+x }-\dfrac{ 1 }{ x }\) Factor the left denominator. Correct. \(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{ 1 }{ x }\)
Now you need to find the LCD of x(x + 1) and x.
so x(x+1) is the lcd so multiply 1/x by x+1?
Correct. Multiply 1/x by (x + 1)/(x + 1) \(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{ 1 }{ x } \times \dfrac{x + 1}{x + 1} \)
now what
\(\Large =\dfrac{ 2 }{ x(x+1) }-\dfrac{x + 1}{x(x + 1)} \)
Now do the actual subtraction. Write a new fraction with the common denominator, and subtract the numerators. Remember to enclose the second numerator in parentheses.
@mathstudent55 huh i goted
x-1/x(x+1)?
so first you have to factor that x square
\(\Large =\dfrac{ 2 - (x + 1)}{ x(x+1) } \) \(\Large =\dfrac{ 2 - x - 1}{ x(x+1) } \) \(\Large =\dfrac{ 1 - x}{ x(x+1) } \)
Numerator is either 1 - x or -x + 1, not x - 1
Sweet! That's one of the answers! THANK YOU I GET IT :)!!
The first step was factoring x^2 + x
Great. You're welcome.
@mathstudent55 nice work!!
Thanks.

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