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anonymous

  • one year ago

The perimeter of a rectangle is 53cm and its width is 11cm . what is the area of the rectangle ? PLZ HELP SOMEONE !!!

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  1. anonymous
    • one year ago
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    Wait I'm confused @mathway

  2. anonymous
    • one year ago
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    What is confusing?

  3. anonymous
    • one year ago
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    Where did u get 35 from ?

  4. anonymous
    • one year ago
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    Kk

  5. anonymous
    • one year ago
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    Lol its okay

  6. anonymous
    • one year ago
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    \[\huge 53=2l+2(11)\]

  7. anonymous
    • one year ago
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    Where did u get 21 from ?

  8. anonymous
    • one year ago
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    Do you know how to solve the perimeter of a rectangle?

  9. anonymous
    • one year ago
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    Hnmm I forgot

  10. anonymous
    • one year ago
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    \(P=2(l+w)\) or \(P=2l + 2w\)

  11. anonymous
    • one year ago
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    Just plug in the numbers. Perimeter= 53 and width=11. Then find the length (\(l\)).

  12. anonymous
    • one year ago
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    Once you've found the length, use the formula in getting the area of a rectangle. \[\huge A=l \times w\]

  13. anonymous
    • one year ago
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    Okay I'll do that

  14. anonymous
    • one year ago
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    Sure! Let me know your answer afterwards. :)

  15. anonymous
    • one year ago
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    Hold on I'm a little confused again

  16. anonymous
    • one year ago
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    What's confusing this time?

  17. anonymous
    • one year ago
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    What should I plug in ?

  18. anonymous
    • one year ago
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    Where?

  19. anonymous
    • one year ago
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    P = 2( L+w) or p = 2L+2w

  20. anonymous
    • one year ago
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    Either way.

  21. anonymous
    • one year ago
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    Now I have 22

  22. anonymous
    • one year ago
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    And the perimeter is 53.

  23. anonymous
    • one year ago
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    I did 53= 2L + 2(11)

  24. anonymous
    • one year ago
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    So it's now...\[53=2l+22\]

  25. mathstudent55
    • one year ago
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    |dw:1439244874901:dw|

  26. anonymous
    • one year ago
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    You subtract 22 on both sides. What did you get?

  27. mathstudent55
    • one year ago
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    The figure above shows the rectangle and the perimeter. 2 sides measure 11 cm each. The entire perimeter measures 53 cm.

  28. anonymous
    • one year ago
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    I'm doing that now @mathway

  29. mathstudent55
    • one year ago
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    |dw:1439245071530:dw|

  30. anonymous
    • one year ago
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    |dw:1439245092875:dw|

  31. anonymous
    • one year ago
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    Awesome! Take your time. :) @Halia

  32. anonymous
    • one year ago
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    I have 31 = 2L

  33. anonymous
    • one year ago
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    |dw:1439245240622:dw|

  34. mathstudent55
    • one year ago
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    |dw:1439245252424:dw|

  35. mathstudent55
    • one year ago
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    The perimeter minus the two known sides is the same as the two unknown sides. 53 cm - 22 cm = 31 cm Since 31 cm is the length of two sides, each side measures 31 cm / 2 = 15.5 cm

  36. mathstudent55
    • one year ago
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    I waited until you wrote this. This pretty much is the side. |dw:1439245350104:dw|

  37. anonymous
    • one year ago
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    Now I'm just confused !!!!!!

  38. anonymous
    • one year ago
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    Is the area 341cm²

  39. anonymous
    • one year ago
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    @Halia Don't worry. I got you. What is the length first?

  40. anonymous
    • one year ago
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    I got 15 for the length @mathway

  41. anonymous
    • one year ago
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    Partly correct, but is that the exact length? The length has a decimal. :)

  42. anonymous
    • one year ago
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    Oh yeah your right

  43. anonymous
    • one year ago
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    So what's the length now? :)

  44. anonymous
    • one year ago
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    15.0 I believe dont I have to divide 31÷2

  45. anonymous
    • one year ago
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    Use your calculator. :)

  46. anonymous
    • one year ago
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    Kk I did it & I got 15.5

  47. anonymous
    • one year ago
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    Great!

  48. anonymous
    • one year ago
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    Now what should I do?

  49. anonymous
    • one year ago
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    And now, for the area (finally!!!), multiply the length and width.

  50. anonymous
    • one year ago
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    \[w=11;~ l=15.5\]

  51. anonymous
    • one year ago
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    Kk I'll do that right now :)

  52. anonymous
    • one year ago
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    \[A=l \times w\]\[A=15.5 \times 11\]

  53. anonymous
    • one year ago
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    Mkay I got 170.5cm²!!!

  54. anonymous
    • one year ago
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    Yes! Great job!

  55. anonymous
    • one year ago
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    Thank you so much for helping me !!! :) I really appreciate it

  56. anonymous
    • one year ago
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    You're welcome! And it was YOU who did the work, not me, so you're awesome! :)

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