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anonymous

  • one year ago

Graph f(x)=2x^2-4, and find the inverse

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  1. anonymous
    • one year ago
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    @peachpi @vera_ewing

  2. anonymous
    • one year ago
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    Did you graph it? and is there a domain restriction for the inverse?

  3. anonymous
    • one year ago
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    yes, i graphed it. What does that mean 'domain restriction'?

  4. anonymous
    • one year ago
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    is there a restriction on the x values? I ask because f(x) is a parabola and it isn't one-to-one which generally means it doesn't have an inverse without the restriction

  5. anonymous
    • one year ago
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    http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIyeF4yLTQiLCJjb2xvciI6IiMwMDAwMDAifSx7InR5cGUiOjEwMDB9XQ-- This is the graph, so not that I can see

  6. anonymous
    • one year ago
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    You can still solve for an inverse using the usual process, but you can only do it for half the function at a time I think. f(x) = 2x² - 4 y = 2x² - 4 Switch x and y and solve for y x = 2y² - 4 x + 4 = 2y² ½x + 2 = y² \[y=\pm \sqrt{\frac{ 1 }{ 2 }x+2}\]

  7. anonymous
    • one year ago
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    okay:) I understand that :)

  8. anonymous
    • one year ago
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    How would you graph the inverse?

  9. anonymous
    • one year ago
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    |dw:1439245043828:dw|

  10. anonymous
    • one year ago
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    If you have points for f(x) reverse them to get points for the inverse. For example (0,-4) and (1, -2) are on f(x). (-4, 0) and (-2, 1) will be on the inverse

  11. anonymous
    • one year ago
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    ohhh! Ok, I get it now:D. So would the inverse be considered a function?

  12. anonymous
    • one year ago
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    no it's not a function because it doesn't pass the vertical line test.

  13. anonymous
    • one year ago
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    okay, thanks so much:)

  14. anonymous
    • one year ago
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    you're welcome

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