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anonymous
 one year ago
Graph f(x)=2x^24, and find the inverse
anonymous
 one year ago
Graph f(x)=2x^24, and find the inverse

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@peachpi @vera_ewing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Did you graph it? and is there a domain restriction for the inverse?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, i graphed it. What does that mean 'domain restriction'?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is there a restriction on the x values? I ask because f(x) is a parabola and it isn't onetoone which generally means it doesn't have an inverse without the restriction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIyeF4yLTQiLCJjb2xvciI6IiMwMDAwMDAifSx7InR5cGUiOjEwMDB9XQ This is the graph, so not that I can see

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can still solve for an inverse using the usual process, but you can only do it for half the function at a time I think. f(x) = 2x²  4 y = 2x²  4 Switch x and y and solve for y x = 2y²  4 x + 4 = 2y² ½x + 2 = y² \[y=\pm \sqrt{\frac{ 1 }{ 2 }x+2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay:) I understand that :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would you graph the inverse?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439245043828:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you have points for f(x) reverse them to get points for the inverse. For example (0,4) and (1, 2) are on f(x). (4, 0) and (2, 1) will be on the inverse

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh! Ok, I get it now:D. So would the inverse be considered a function?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no it's not a function because it doesn't pass the vertical line test.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, thanks so much:)
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