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anonymous

  • one year ago

There are 6 red marbles, 9 blue marbles, and 10 green marbles in a bag. What is the theoretical probability of randomly drawing a red marble and then a green marble?

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  1. anonymous
    • one year ago
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    depends entirely on whether you replace the marble or not after the first one is drawn

  2. anonymous
    • one year ago
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    The first one is not replaced.

  3. anonymous
    • one year ago
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    oh wait NOT replaced lets go slow

  4. anonymous
    • one year ago
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    what is the probability the first one is red?

  5. anonymous
    • one year ago
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    i hope that is more or less obvious it is the ratio of the number or red marbles to the total number of marbles

  6. anonymous
    • one year ago
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    24%?

  7. anonymous
    • one year ago
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    There are 4 answers: 10% 9.6% 16% 64%

  8. anonymous
    • one year ago
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    not really interested in percents before we compute these numbers we need fractions first, then we can turn the final answer in to a percent

  9. anonymous
    • one year ago
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    \[\frac{ 24 }{100}?\]

  10. anonymous
    • one year ago
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    lets go slow how many red marbles are there?

  11. anonymous
    • one year ago
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    6

  12. anonymous
    • one year ago
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    yes, and how many marbles are there total?

  13. anonymous
    • one year ago
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    25

  14. anonymous
    • one year ago
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    right so the probability of picking a red marble first is \[\frac{6}{25}\]

  15. anonymous
    • one year ago
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    now the red marble is chosen, and apparently not replaced how many green marbles are there ?

  16. anonymous
    • one year ago
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    10

  17. anonymous
    • one year ago
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    and how many marbles are left in the bag?

  18. anonymous
    • one year ago
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    24

  19. anonymous
    • one year ago
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    so the probability of picking a green marble once one red one is removes is?

  20. anonymous
    • one year ago
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    \[\frac{ 10 }{ 24 }\]?

  21. anonymous
    • one year ago
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    yes

  22. anonymous
    • one year ago
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    to compute the probability that both things occur, multiply

  23. anonymous
    • one year ago
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    \[\frac{6}{25}\times \frac{10}{24}\]

  24. anonymous
    • one year ago
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    \[\frac{ 60 }{ 600 }\]

  25. anonymous
    • one year ago
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    better known on planet earth as \(\frac{1}{10}\)

  26. anonymous
    • one year ago
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    or \(0.1\) or even \(10\%\)

  27. anonymous
    • one year ago
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    So that's the answer?

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