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depends entirely on whether you replace the marble or not after the first one is drawn

The first one is not replaced.

oh wait NOT replaced lets go slow

what is the probability the first one is red?

24%?

There are 4 answers:
10%
9.6%
16%
64%

\[\frac{ 24 }{100}?\]

lets go slow
how many red marbles are there?

yes, and how many marbles are there total?

25

right
so the probability of picking a red marble first is
\[\frac{6}{25}\]

now the red marble is chosen, and apparently not replaced
how many green marbles are there ?

10

and how many marbles are left in the bag?

24

so the probability of picking a green marble once one red one is removes is?

\[\frac{ 10 }{ 24 }\]?

yes

to compute the probability that both things occur, multiply

\[\frac{6}{25}\times \frac{10}{24}\]

\[\frac{ 60 }{ 600 }\]

better known on planet earth as \(\frac{1}{10}\)

or \(0.1\) or even \(10\%\)

So that's the answer?