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anonymous

  • one year ago

What is the probability of getting a sum less than 11 when a pair of dice are rolled ?

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  1. anonymous
    • one year ago
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    @mathway can you help me ?

  2. anonymous
    • one year ago
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    possible events for a sum of 11 or more than 11 are 56,65,66 no. of events=3 total no. of events=36 P(for a sum 11 or more )=3/36=1/12 P(for a sum less than 11)=1-1/12=?

  3. anonymous
    • one year ago
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    I'm confused !!! @surjithayer

  4. anonymous
    • one year ago
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    What fraction I'm I multiplying ?

  5. anonymous
    • one year ago
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    @mathstudent55 do u mind helping me out ?

  6. mathstudent55
    • one year ago
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    The probability of an event happening is the number of ways the even can happen divided by the total number of ways. When you roll 2 dice, what is the total number of outcomes?

  7. anonymous
    • one year ago
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    There 6 outcomes

  8. mathstudent55
    • one year ago
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    Below you see all possible outcomes of rolling 2 dice. How many outcomes are there? 11, 12, 13, 14, 15, 16 21, 22, 23, 24, 25, 26 31, 32, 33, 34, 35, 36 41, 42, 43, 44, 45, 46 51, 51, 53, 54, 55, 56 61, 62, 63, 64, 65, 66

  9. mathstudent55
    • one year ago
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    One single die has 6 outcomes, but when you roll two dice, you need to find all possible combinations of outcomes of the two.

  10. anonymous
    • one year ago
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    I'm guessing there are 2 I'm not sure

  11. mathstudent55
    • one year ago
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    Look above. Each pair of numbers is a different outcome. There are 36 possible different outcomes.

  12. anonymous
    • one year ago
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    Kk I got it

  13. mathstudent55
    • one year ago
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    When a pair of dice are rolled, there are 36 possible different outcomes. Now you need to find out how many of the 36 different outcomes have a sum less than 11.

  14. anonymous
    • one year ago
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    & how would I do that ?

  15. mathstudent55
    • one year ago
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    You add the numbers of the two dice. All outcomes in black below are less than 11. The outcomes in red are 11 or more. \(11, 12, 13, 14, 15, 16 \) \(21, 22, 23, 24, 25, 26 \) \(31, 32, 33, 34, 35, 36 \) \(41, 42, 43, 44, 45, 46 \) \(51, 51, 53, 54, 55, \color{red}{56} \) \(61, 62, 63, 64, \color{red}{65}, \color{red}{66}\)

  16. mathstudent55
    • one year ago
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    Out of 36 outcomes, only 3 are 11 or more. That means 33 are less than 11.

  17. anonymous
    • one year ago
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    So the probability of getting a sum less than 11 when a pair of dice are rolled are 33/36?

  18. mathstudent55
    • one year ago
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    Now you see that your desired outcomes are 33,and the total outcomes are 36. The probability of rolling a number less than 11 is \(p(less~ than~ 11) = \dfrac{33}{36} \)

  19. mathstudent55
    • one year ago
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    Correct. Now you need to reduce 33/36.

  20. anonymous
    • one year ago
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    Which is 11/12 ?

  21. mathstudent55
    • one year ago
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    Correct.

  22. anonymous
    • one year ago
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    Kk once again thanks I appreciate it :) @mathstudent55

  23. mathstudent55
    • one year ago
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    You're welcome.

  24. anonymous
    • one year ago
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    \[1-\frac{ 1 }{ 12 }=\frac{ 12-1 }{ 12 }=\frac{ 11 }{ 12 }\]

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