Sid brought $200 to the amusement park . The cost of admission is $16.25, and the cost of a lunch is $6.50. After Sid purchased an admission ticket and a lunch ticket for each person in his group, he had $18.25 left. How many people are Sid's group?
For my answer i Got that theres 7 people in his group Can someone check to see if im correct/accurate
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i do not think it's 7 cause when i multiplied and added everything up it wasn't 7
I'll let x represent the number of people
I think I did the math right
For the answer choices 8 isn't one of them @taramgrant0543664
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Sid brought $200 to the park and had only $18.25 left so $181.75 was spent
price of admission is $16.25
for a sack lunch it's $6.50
so $16.25+$6.50 = $22.75. per person hmmmmmm.
181.75/22.75 = 7.98901
the problem is that there is no such thing as a .9 person. -_-!
round that number up and it's approx. 8 ???
what about... money spent/ number of people ?
181.75 / 4 = 45.44
181.75 / 5 = 36.35
181.75 / 6 = 30.29
181.75 / 7 = 25.96
To be honest I think the answer is 7
181.75/7.9 = 23.00
181.75/8 = 22.71875 = 22.72
if there were 7 people, that guy will still have some spare change
$25.96 - 22.75 = $3.21
maybe it's one of those common core guestimating problems.
I really don't know there's probably a error in this problem
Let's go to a different problem
I've read that common core problem have guestimates as answers as opposed to the real thing
like for example we all know that 3 x 5 = 15
but according to common core 3 x 4 is 13 or something like that what the heck?!
x = 181.75/22.75 = 7.98901
181.75/7.98901 = 22.75000 = 22.75
but a .98 person doesn't make sense. so .. 7 will have to be the closest if we had to respect the answer choices. a la carte common core