anonymous
  • anonymous
can anyone check my work? A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1st shot 2nd shot total miss: 40% 5% 45% make: 60% 95% 155% total: 100% 100% 200% probability of missing both free throws = 45%
mathstudent55
  • mathstudent55
The probability of missing the first shot is 40%. When she misses the first shot, the probability of missing the second shot is very, very low, only 5%. That means that the probability of missing both shots must be much smaller than the probability of missing the first shot. 40/100 * 5/100
anonymous
  • anonymous
0.02?

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mathstudent55
  • mathstudent55
Yes, it's 0.02 which is equal to 2%.

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