anonymous
  • anonymous
A statue is made up of iron and nickel in a ratio of 2:7 . If the statue weighs 81 pounds, what is the weight of the nickel in the statue ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@UsukiDoll can you help me out ?
ccswims
  • ccswims
2+7 = 9 81/9 = 9
ccswims
  • ccswims
multiply 2 by 9 and 7 by 9

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ccswims
  • ccswims
then you get the weight of the nickel
UsukiDoll
  • UsukiDoll
sorry I was helping with another question.. I'll do verification in a bit.
anonymous
  • anonymous
@cc swims I did it
anonymous
  • anonymous
I got 18 & 63
mathstudent55
  • mathstudent55
If the statue has a ratio of iron to nickel of 2:7, it could have: iron nickel 2 * 1 lb + 7 * 1lb 2 * 2 lb + 7 * 2 lb 2 * 3 lb + 7 * 3 lb 2 * 4 lb + 7 * 4 lb All the above are in a 2:7 ration, but we don't know which number to multiply both parts of the ratio by, so we call that unknown x. The ratio is 2x : 7x Since the total weight is 81 lb, we write the equation 2x + 7x = 81 9x = 81 x = 9 Then 2x = 2(9) = 18, and 7x = 7(9) = 63 The statue has 18 lb of iron and 63 lb of nickel.
anonymous
  • anonymous
Thanks @mathstudent55 :)
mathstudent55
  • mathstudent55
You're welcome.

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