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anonymous

  • one year ago

A statue is made up of iron and nickel in a ratio of 2:7 . If the statue weighs 81 pounds, what is the weight of the nickel in the statue ?

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  1. anonymous
    • one year ago
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    @UsukiDoll can you help me out ?

  2. ccswims
    • one year ago
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    2+7 = 9 81/9 = 9

  3. ccswims
    • one year ago
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    multiply 2 by 9 and 7 by 9

  4. ccswims
    • one year ago
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    then you get the weight of the nickel

  5. UsukiDoll
    • one year ago
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    sorry I was helping with another question.. I'll do verification in a bit.

  6. anonymous
    • one year ago
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    @cc swims I did it

  7. anonymous
    • one year ago
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    I got 18 & 63

  8. mathstudent55
    • one year ago
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    If the statue has a ratio of iron to nickel of 2:7, it could have: iron nickel 2 * 1 lb + 7 * 1lb 2 * 2 lb + 7 * 2 lb 2 * 3 lb + 7 * 3 lb 2 * 4 lb + 7 * 4 lb All the above are in a 2:7 ration, but we don't know which number to multiply both parts of the ratio by, so we call that unknown x. The ratio is 2x : 7x Since the total weight is 81 lb, we write the equation 2x + 7x = 81 9x = 81 x = 9 Then 2x = 2(9) = 18, and 7x = 7(9) = 63 The statue has 18 lb of iron and 63 lb of nickel.

  9. anonymous
    • one year ago
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    Thanks @mathstudent55 :)

  10. mathstudent55
    • one year ago
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    You're welcome.

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