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anonymous
 one year ago
Solve the following system of equations and show all work.
y = x2 + 3
y = x + 5
anonymous
 one year ago
Solve the following system of equations and show all work. y = x2 + 3 y = x + 5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know we have to multiply them by something to be able to cross the variables out or something, I'm not sure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have a better idea

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since the y's have to be the same, set \[x^2+3=x+5\] and solve the resulting quadratic equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0seems reasonable find the y values too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I actually do not now how

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I skimmed over everything and i'm regretting it at the moment

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0of course you know how!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know \(x=2\) replace \(x\) by 2 in either \(y=x^2+3\) or \(y=x+5\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you will get the same number in both cases (since they intersect there) then repeat with \(x=1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can do it in your head right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so one solution is \((2,7)\) and the other you get when \(x=1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not fully understanding, I'm sorry :( could you explain?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you found two solutions for \(x\) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one is \(x=2\) and if \(x=2\) the \(y=7\) in both equations so one point of intersection is \((2,7)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the other solution you got was \(x=1\) and if you replace \(x\) by \(1\) in either equation above you get \(4\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since \(y=1+5=4\) and also \(y=(1)^2+3=4\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0therefore the other point of intersection (there are two of them, one for each \(x\)) is \((1,4)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how is that for an explanatation? not sure i can do any better except maybe it is worth mentioning that the graph of \(y=x^2+3\) is a parabola, and it intersects the graph of \(y=x+5\) (a line) in two places

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the final answer would be (1,4)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no there are two answers
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