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anonymous
 one year ago
Solve and see whether or not it is extraneous
4/x^2+3x10 1/x^2+x6 = 3/x^2x12
anonymous
 one year ago
Solve and see whether or not it is extraneous 4/x^2+3x10 1/x^2+x6 = 3/x^2x12

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now it gets real annoying real fast factor the denominators first i suck at factoring so let me know what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright hold on lol:)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04/(x2)(x+5) 1/(x2)(x+3)= 3(x4)(x+3) @satellite73 done :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then you can clear the fractions as before but this time you have to multiply by the least common multiple of the denominators which is \[(x2)(x+5)(x+3)(x4)\] ugh

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh..oh gosh...headachee

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually it is not that bad, since the numerators are all numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[4(x+3)(x4)1(x+5)(x4)=3(x+5)(x2)\] i think check it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is really just cancelling what you need to cancel

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then we have a raft of algebra to do multiply all this muck out, combine like terms etc etc i refuse to do it, i would cheat

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha! I totally agree:) Ok, lets move onto another one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol actually all the \(x^2\) terms go bye bye and you end up with only \(14x=2\) so \(x=\frac{1}{7}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here is how to cheat http://www.wolframalpha.com/input/?i=4%28x%2B3%29%28x4%291%28x%2B5%29%28x4%29%3D3%28x%2B5%29%28x2%29

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and since \(\frac{1}{7}\) does not make any denominator zero, it is NOT extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Marry me? Lol jk! Thanks so much :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and sure why not? it can be an OS wedding

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Perfect! I'll start planning :D
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