anonymous
  • anonymous
graph and find the inverse of f(x)=2x^2-4. Once you find the inverse, graph it too.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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zzr0ck3r
  • zzr0ck3r
This only has a restricted inverse since the function is not 1-1
anonymous
  • anonymous
too bad it doesn't have an inverse ...
zzr0ck3r
  • zzr0ck3r
and what I mean is that it does not have an inverse :)

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More answers

anonymous
  • anonymous
Hmm..so would I just graph f(x)=2x^2-4 and then say it doesnt have an inverse?
zzr0ck3r
  • zzr0ck3r
You can say that by the definition of an inverse, it must be 1-1 and it is not.
anonymous
  • anonymous
Thanks :)
zzr0ck3r
  • zzr0ck3r
or I guess graph it and draw a horizontal line through any two points to show it is not 1-1
anonymous
  • anonymous
What about y=-3x+6? I got -x+3/6 as the inverse
zzr0ck3r
  • zzr0ck3r
hmm
zzr0ck3r
  • zzr0ck3r
\(y=-3x+6\) Switch the \(x\) and the (y\) and solve for \(y\). \(x=-3y+6\\ x-6=-3y\\ \dfrac{x-6}{-3}=y\\ y=\dfrac{6-x}{3}\)
anonymous
  • anonymous
not to butt in but you can still solve \[2y^2-4=x\]for \(y\) to find an inverse, it just won't be a function
zzr0ck3r
  • zzr0ck3r
or restrict the domain on the first one
anonymous
  • anonymous
add 4, divide by 2 and you get \[y^2=\frac{x+4}{2}\] but when you solve for \(y\) you get \[y=\pm\sqrt{\frac{x+4}{2}}\]
anonymous
  • anonymous
the \(\pm\) make it not a function
zzr0ck3r
  • zzr0ck3r
\(f:\mathbb{R}^+\rightarrow R, f(x) = 2x^2-4\) has as its inverse a proper function.
zzr0ck3r
  • zzr0ck3r
I think they meant, use the graph to determine if it has an inverse.
anonymous
  • anonymous
Thanks guys:D

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