anonymous
  • anonymous
HELP!!! The surface area of two similar rectangular prisms are 361m2 and 441m2. What is the scale factor of the larger prism to the smaller prism? A.) 361/441 B.) 19/21 C.) 21/19 D.) 19/11
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@ganeshie8 please help
anonymous
  • anonymous
@Nnesha
anonymous
  • anonymous
@nincompoop

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More answers

ganeshie8
  • ganeshie8
Hint : If areas of similar figures are in ratio \(\dfrac{a}{b}\), then the lengths(scale factors) will be in ratio \(\dfrac{\sqrt{a}}{\sqrt{b}}\)
anonymous
  • anonymous
so i just take each answer choice and do that to them??
anonymous
  • anonymous
i'm still not understanding
ganeshie8
  • ganeshie8
Yes, first setup the ratio of areas
anonymous
  • anonymous
is it 19/21
ganeshie8
  • ganeshie8
careful, they want larger prism on top
ganeshie8
  • ganeshie8
ratio of areas = \(\dfrac{441}{361}\)
anonymous
  • anonymous
so its C?
ganeshie8
  • ganeshie8
so, ratio of scalefactors = \(\dfrac{\sqrt{441}}{\sqrt{361}}=?\)
anonymous
  • anonymous
21/19
ganeshie8
  • ganeshie8
Yep!
anonymous
  • anonymous
i have another question if thats ok
ganeshie8
  • ganeshie8
sure ask
anonymous
  • anonymous
The two cones are similar. Find the surface area of the larger cone. Round your answer to the nearest hundredth. A. 810.28 B. 847.80 C. 868.30 D. 886.25
anonymous
  • anonymous
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anonymous
  • anonymous
@ganeshie8
anonymous
  • anonymous
S=π×11.12+π×11.1×13.8 is the formula, solve that and u will get the answer
anonymous
  • anonymous
I got 516..../
anonymous
  • anonymous
that's not right
anonymous
  • anonymous
hmm let me solve and see what i get
anonymous
  • anonymous
ok
anonymous
  • anonymous
i am sorry the same question is on open study and I checked the formula I am so sorry I was not able to help
anonymous
  • anonymous
i feel bad :(
anonymous
  • anonymous
its ok. @ganeshie8 can you help
anonymous
  • anonymous
thnx

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