A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Graph 3/x^24. Then find the domain/range/VA
anonymous
 one year ago
Graph 3/x^24. Then find the domain/range/VA

This Question is Closed

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x) = \frac{ 3 }{ x^2 }4?\] is this your equation, think of the parent function, which in this case is \[\frac{ 1 }{ x^2 }\] it looks like dw:1439265308847:dw you can get this by simply making a table of values which you can do yourself. Once you have your parent function now we can do our transformations. \[y = \frac{ 3 }{ x^2 }\] where the 3 should give you a scaling factor then afterwards add the 4, \[y = \frac{ 3 }{ x^2 }4\] where the 4 should give you a vertical translation of 4 units. If you're not comfortable at seeing it directly you can always make a table of values for each step, good luck!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No:( It is dw:1439336098501:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That means you're graph will look like this then dw:1439336233138:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Actually here, use this site to graph it out, but make sure you know how the transformations work https://www.desmos.com/calculator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks:)! What about the domain, range

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1For domain solve \[x^2  4 \neq 0\] solve for x

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Notice that domain occupies the x values, and range is the y values so you have y>0 and \[y \le 3/4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok:) And what about the VA? I have no idea what that means haha

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1vertical asymptotes

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I'm assuming you don't know what limits are, so you see where it's not defined

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So VA is at x = 2 and x = 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And last one, I promise :) It says find the HA/SA???

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I don't know what SA is but HA is horizontal asymptote

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so would that be 3/2?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Not quite, since the denominator has a higher degree than the numerator it's 0

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That's just a shortcut though

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You should actually look up what exactly this stuff means haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol! I probably should :) and I will

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so just checking, so far we have: VA=2,2 Dall real numbers ry<=3/4

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1domain is not all real numbers

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1X cannot be 2 and 2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[D: x \in \mathbb{R}: x \neq \pm 2\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1It's all real except for + and  2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[R: y \in \mathbb{R}: y \le  \frac{ 3 }{ 4 } ~or~y>0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So going back to the horizontal asym., I sort of get it know : http://www.purplemath.com/modules/asymtote2.htm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be 3/x^2?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1and if the degree in the numerator was greater you'd have no horizontal asymptote, so like (x^3+2)/(x^2+3) no HA
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.