mmend98
  • mmend98
Which of the following is not true about beta emissions? Difference of the atomic number by one between the old element and new element formed Are written as 0-1e Cannot penetrate concrete Less penetrating than alpha emissions
Chemistry
schrodinger
  • schrodinger
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mmend98
  • mmend98
mmend98
  • mmend98
taramgrant0543664
  • taramgrant0543664
Well which one are you thinking it is? I'll cross one off for you, beta emissions are unable to pass through concrete but it can pass through something like paper.

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taramgrant0543664
  • taramgrant0543664
So it is not C
mmend98
  • mmend98
Its asking what it not is. So C would be the answer right?
Zale101
  • Zale101
Here's a hint: Beta particles are high speed electrons, travels faster, and are less heavily ionized than alpha particles.
taramgrant0543664
  • taramgrant0543664
C says cannot penetrate concrete so that's true the question asks what is not true
mmend98
  • mmend98
oh lol sorry
mmend98
  • mmend98
Thanks Zale it would be D
taramgrant0543664
  • taramgrant0543664
It's ok!
taramgrant0543664
  • taramgrant0543664
And yes it would be D
Zale101
  • Zale101
Yes it is D. because since beta particles are less heavily ionized then that makes it more penetrating than alpha particles. Alpha particles are thickly ionized and are less penetrating.
mmend98
  • mmend98
Given the following chemical equation, how many moles of carbon are necessary to react with 5.52 moles of SO2? 5C(s) + 2SO2 (g) arrow CS2 (l) + 4CO (g) 5.52 moles SO2 2.00 moles SO2 13.8 moles SO2 11.0 moles SO2 this one would be 13.8 right ? because the formula is 5.52molesSO2×5molesC2molesSO2=13.8
Zale101
  • Zale101
are you familiar wit mole to mole ratio?
Zale101
  • Zale101
with*
mmend98
  • mmend98
yea im familiar did i do it right ? thats what im asking lol
Zale101
  • Zale101
Yes. Sorry, i did not see it.
mmend98
  • mmend98
thats ok mate
mmend98
  • mmend98
Fusion refers to the splitting of an atomic nucleus into fragments of roughly the same mass amount. True False
taramgrant0543664
  • taramgrant0543664
13.8 would be correct
mmend98
  • mmend98
Fusion refers to the splitting of an atomic nucleus into fragments of roughly the same mass amount. True False
Zale101
  • Zale101
What do you think? True or false? Make any educated guess
Zale101
  • Zale101
Search Nuclear Fission and see if it matches the definition.
mmend98
  • mmend98
the educated guess i would make is false
mmend98
  • mmend98
i just never know with this weird wording tbh
taramgrant0543664
  • taramgrant0543664
That is referring to fission which is the splitting, fusion is the colliding of atoms
Zale101
  • Zale101
Yep. False because what Tara stated above ^
mmend98
  • mmend98
Given a solution with a pH of 2.8, what is the [H+] of the solution? 2.8 M 6.31 x 10-12 M 1.58 x 10-3 M 11.2 M
mmend98
  • mmend98
this one would be c?
taramgrant0543664
  • taramgrant0543664
Yes it would be c [H+]=10^-2.8 Which gives c
mmend98
  • mmend98
A solution is highly concentrated if there is: a large volume of solution a large amount of solvent and a small amount of solute a large amount of solute and a small amount of solvent a high density value for the solution
mmend98
  • mmend98
im confused on this one for some reason tara lol
mmend98
  • mmend98
youve been unreal help btw
taramgrant0543664
  • taramgrant0543664
Well when you think about it volume of solution doesn't matter because it could be at any volume and density value doesn't make sense for it either. Think about the difference between something dilute and something that is concentrated and that will sort out between B and C
mmend98
  • mmend98
it would be b
taramgrant0543664
  • taramgrant0543664
And no problem I enjoy helping and once my SS gets a little higher I am planning on applying for the qualified helper in chemistry so I'm glad to hear that I'm helping!
mmend98
  • mmend98
it would be b right ?
taramgrant0543664
  • taramgrant0543664
dilute: a solution that contains a small proportion of solute relative to solvent concentrated: a solution that contains a large proportion of solute relative to solvent.
mmend98
  • mmend98
oh lol its c
mmend98
  • mmend98
im dumb af
taramgrant0543664
  • taramgrant0543664
No you're not it was a little mistake that happens, I've made a lot of mistakes it happens but that's how you learn
mmend98
  • mmend98
Calculate the change in freezing point when 116.8 grams of barium chloride are added to 250 grams of water. Kf = 1.86°C/m; Kb = 0.512°C/m -4.17°C -12.5°C -8.35°C 0°C last question im stuck on
taramgrant0543664
  • taramgrant0543664
ΔT= Kf · m · i So ΔT is the change in temperature that you solve for Kf is given m is the molarity to find this you need to find the moles of barium chloride and you need to convert 250g of water into kg. then you do moles divided by kg of water to find m i is the van't Hoff dissociation factor so BaCl2 dissociates into Ba2+ +2Cl- let me double check this i, I can't quite remember the rule but the rest is right I'll look it up quick
taramgrant0543664
  • taramgrant0543664
So BaCl2 breaks into Ba2+ and 2Cl- so it breaks into 3 parts so i is 3 but NaCl for example breaks into Na+ and Cl- so i=2
taramgrant0543664
  • taramgrant0543664
If we put it all together ΔT= Kf · m · i ΔT= (1.86)m(3) so m just needs to be found
mmend98
  • mmend98
i got A ?
taramgrant0543664
  • taramgrant0543664
How did you get a negative? What did you get for m?
mmend98
  • mmend98
wait i got D i forgot to multiply one term.
taramgrant0543664
  • taramgrant0543664
Oh wait it's suppose to be negative don't mind me it's a little late not really thinking for a second there lol
mmend98
  • mmend98
then i think it has to be a.\
taramgrant0543664
  • taramgrant0543664
I got something different what did you get for m?
mmend98
  • mmend98
what did u get then ill check mine over
taramgrant0543664
  • taramgrant0543664
I got 2.24 as my m value
mmend98
  • mmend98
i got 5.2
mmend98
  • mmend98
idek how
taramgrant0543664
  • taramgrant0543664
116.8g/ molar mass of BaCl2 (208.233)=0.5609 0.5609/ kg of water so 250/1000 this =2.24
mmend98
  • mmend98
i got B
mmend98
  • mmend98
yes your correct
taramgrant0543664
  • taramgrant0543664
Yes B would be correct!
mmend98
  • mmend98
Given a solution with a pOH of 13.6, what is the [OH-] of the solution? 13.6 M 2.51 x 10-14 M 0.4 M 3.98 x 10-1 M would be a?
mmend98
  • mmend98
im sorry if its too late go ahead and have a great night !! u were amazing
taramgrant0543664
  • taramgrant0543664
I can check this last one quick for you just give me one sec
mmend98
  • mmend98
thanks Tara
taramgrant0543664
  • taramgrant0543664
pOH=-log[OH-] 13.6=-log[OH-] -13.6=log[OH-] 10^(-13.6)=[OH-] It's not A
mmend98
  • mmend98
B is what i got
mmend98
  • mmend98
see this is why i ask u ;) haha
taramgrant0543664
  • taramgrant0543664
Yes B is correct
mmend98
  • mmend98
so its 2.51 x 10-14 M ?
mmend98
  • mmend98
sweet
taramgrant0543664
  • taramgrant0543664
Yes it is!

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