## anonymous one year ago A study of one thousand teens found that the number of hours they spend on social networking sites each week is normally distributed with a mean of 10 hours. The population standard deviation is 2 hours. What is the 95% confidence interval for the mean? 9.88−10 hours 10−10.12 hours 9.88−10.12 hours 9.76−10.24 hours

0.196 is the constant for a 95% confidence interval Lower limit =Mean - (0.196) x$\frac{ Standard deviation value }{ \sqrt{mean}}$ Upper limit =Mean + (0.196) x $\frac{ Standard deviation value }{ \sqrt{mean}}$