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anonymous
 one year ago
Need Help! Evaluate the integral (1x/x)^2 *dx
anonymous
 one year ago
Need Help! Evaluate the integral (1x/x)^2 *dx

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439271323768:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1whats stopping you from expanding and working each term ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I did it, but I got stuck on one part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439271526217:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What happens after this...because the solution manual is saying something else

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1looks good! expand that out using the identity \[(ab)^2=a^22ab+b^2\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439271609165:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\left(\frac{1}{x}1\right)^2=?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OH thats what they did

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, I totally forgot about the identity and was wondering how they came up with the middle term

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1it helps to review basic algebraic and trig identities while doing integrals

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would honestly love doing integrals....but theres just so much algebra

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Exactly! calculus is always easy, its just the algebra part that is hard

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1its not hard as such, its just pain

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol tell me about it, I have my final in a few days..and im freaking out Either way, how is the middle term 2/x , im getting +2/x

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[(ab)^2=a^2\color{red}{}2ab+b^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would be 2*(1/x)*(1), right?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\left(\frac{1}{x}1\right)^2=\frac{1}{x^2}\frac{2}{x}+1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But the middle part is 2*(1/x)*(1), so wouldnt that make it +2/x instead of 2/x?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\left(\frac{1}{x}1\right)^2=(\frac{1}{x})^22(\frac{1}{x})(1)+1^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why dont we multiply by negative, because isnt that the b value?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(a = \frac{1}{x}\) \(b=1\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1don't forget to integrate the terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also, how do we integrate 1/x^2?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ x^2 } = x^{2} ~~~~~\int\limits \frac{ 1 }{ x^2 } dx = \int\limits x^{2} dx = \frac{ x^{1} }{ 1 }+C =  \frac{ 1 }{ x }+C\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nvm, I watched this video https://www.youtube.com/watch?v=ZFZRid582Lk, and even though its in spanish...I figured it out, thanks though astro

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1here is a trick question, \[\int \frac{1}{x}~dx = ?\] @mary_am

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1nvm that video is a spoiler

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0k im not dumb.. I knew what ∫1x dx was

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Ofcourse you're not, I see :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0I am dumb, and yes I am xD

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Sounds about right

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Eihsenag university

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0We enjoy helping people, it's a good way to learn ourselves :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Thank you and you to!
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