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anonymous

  • one year ago

My last question, any help?

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  1. anonymous
    • one year ago
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    How do you solve this?

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  2. Michele_Laino
    • one year ago
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    hint: by definition, we can write this: \[\Large \left( {g \circ f} \right)\left( x \right) = g\left( {f\left( x \right)} \right)\]

  3. anonymous
    • one year ago
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    Just taking a wild guess here, but would that make the answer D?

  4. anonymous
    • one year ago
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    It is not.

  5. anonymous
    • one year ago
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    \[If f(x)=3x^2-2x-1\] and \[ g(x)=x^2\] Since (x) in g(x) got replaced by a f(x) and \[f(x)=3x^2-2x-1\]

  6. anonymous
    • one year ago
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    then \[3x^2-2x-1 \] would replaced the x in \[g(x)=x^2\]

  7. anonymous
    • one year ago
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    which leads to \[(3x^2-2x-1)^2\] g o f means g has a f inside that leads to g(f(x)) meaning the g(x) needs to be plugged in with f(x) instead.

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spraguer (Moderator)
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