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jiteshmeghwal9
 one year ago
Find general solution of \(x\) in the equation : \[sin6x=sin4xsin2x\]
jiteshmeghwal9
 one year ago
Find general solution of \(x\) in the equation : \[sin6x=sin4xsin2x\]

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3hint: your equation, can be rewritten as follows: \[\Large \sin \left( {4x} \right) = \sin \left( {6x} \right) + \sin \left( {2x} \right)\]

jiteshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.1\[\sin4x=2\sin4xcos2x\]\[\sin4x(12\cos2x)=0\]\[x=\frac{n \pi}{4}\]&\[2x=2n \pi \pm \frac{\pi}{3}\]\[x=n \pi \pm \frac{\pi}{6}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.3yes! exact that was my idea
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