## jiteshmeghwal9 one year ago Find general solution of $$x$$ in the equation :- $sin6x=sin4x-sin2x$

1. Michele_Laino

hint: your equation, can be rewritten as follows: $\Large \sin \left( {4x} \right) = \sin \left( {6x} \right) + \sin \left( {2x} \right)$

2. jiteshmeghwal9

$\sin4x=2\sin4xcos2x$$\sin4x(1-2\cos2x)=0$$x=\frac{n \pi}{4}$&$2x=2n \pi \pm \frac{\pi}{3}$$x=n \pi \pm \frac{\pi}{6}$

3. Michele_Laino

yes! exact that was my idea

4. jiteshmeghwal9

thanx

5. Michele_Laino

:)