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anonymous
 one year ago
Man has a varying displacements ranging from 1.0m,2.0m and 3.0m from his starting position and he had initial velocity of 2.0m/s and acceleration of 2.0m/s^2. Calculate the time elapsed at times when he is exactly at the 1.0m, 2.0m, 3.0m displacement from his starting point. Formula required. I am actually stuck with the formula that may or may not require quadratic solution to isolate (t). Anyone?
anonymous
 one year ago
Man has a varying displacements ranging from 1.0m,2.0m and 3.0m from his starting position and he had initial velocity of 2.0m/s and acceleration of 2.0m/s^2. Calculate the time elapsed at times when he is exactly at the 1.0m, 2.0m, 3.0m displacement from his starting point. Formula required. I am actually stuck with the formula that may or may not require quadratic solution to isolate (t). Anyone?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Excuse me the acceleration is 0.5m/s^2 actually

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1This is a physics Q, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can also be mathematically computed as well.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's hard to tell if a question should belong to physics or maths

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1Aww just how much I love being called ''Sir'' :D

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Robert136 It's hard to tell if a question should belong to physics or maths \(\color{blue}{\text{End of Quote}}\) Nah mate, so easy to tell! But in some cases it may not be so easy. Your not wrong.

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1I have a question. Does the question mean displacements or positions of 1, 2, and 3 m?

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1Oh, it doesn't give an initial position, so it is displacement. So, can you write or type the quadratic equation you've found?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah the initial position is 0.00m right on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's supposed to go negative position for a while whilst the initial velocity holds negative but then due to acceleration it's turned to positive and eventually you know what's happening

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0d=v(initial)*t+1/2(a)t^2 Where d=displacement or distance v=velocity t=time taken

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's quid spot on how this equation is supposed to work to compute the distance or displacement.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0However, it's unclear as to whether d stands for displacement or distance in this given situation

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1This equation is for displacement. So, here's what's awesome about it. You don't have to worry about the fact that the man has an initial negative velocity and will have negative displacements. All you have to do is use d = 1.0, 2.0, and 3.0 m.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I plug in any of the given values being investigated and leave out the t and t squared, which is bit of a problem because then quadratic formula needs a peek

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1It's great that you recognize what the guy is actually doing, though! :D Right, you don't substitute anything for t because that's what you're solving for.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use the equation \[\vec s=\vec ut+\frac{1}{2}\vec a t^2\] As this looks like a question in 1D, you can simply replace vectors with scalars accompanied by appropriate plus or minus sign

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the vector s is displacement

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1d = v0 * t + (1/2)a*t^2 1.0 = 2t + (1/2)(0.5)t^2 0 = 1  2t + 0.25t^2 And once you have this, you can solve using the quadratic formula or by graphing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here's the deal, as you are dealing in 1 dimension, you can only move forward or backward, like along a line. So you can assign either the forward or the backward direction a positive sign and it's opposite direction as negative so if a quantity is given as positive and another quantity is given as negative, what they are basically saying is they are in the opposite direction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's indicated by positive and negative sign here.

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1To be clear, when I say "graph it", I mean you'll input y = 1  2t + 0.25t^2 and the find its zeroes and your calculator will use x instead of t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right. I need to find the roots which would have two obviously but I need to pick the positive one because negative one will be unrealistic to even assume it exists.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's why I love physics

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0relatively less math to deal with but with more intuitive reasoning

Miracrown
 one year ago
Best ResponseYou've already chosen the best response.1Physics is the mother of science
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