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anonymous
 one year ago
What net force is required to bring a 1500 kg car to rest from a speed of 108 km/h in 15 s?
anonymous
 one year ago
What net force is required to bring a 1500 kg car to rest from a speed of 108 km/h in 15 s?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0108km/h/3600s=0.03km/s=30m/s 0=0.03km/s+15s*(a) 0.03/s=15s*(a) a=0.03/15 a=0.002km/s^2=2m/s^2 also Where F is the force and m is the mass as well as a being the acceleration F=2m/s^2*1500kg=3000N

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can someone verify this for me please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did the conversion from kilometers per hour to meters per second to comply with the rules of F=ma and then the rest consists of finding the acceleration and dividing with the correct mass to find the right answer .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Overall my answer says I would need 3000N force to stop a truck weighing 1500kg from the velocity of 108km/h to rest within 15 seconds.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does that seem realistic overall or should I reconsider the solution thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well I can't question your authority so yeah I think soXD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you are right but it should be \[F=3000N\] The force is acting in opposite direction to the vehicle, and this shows the retarding nature of the force the absolute value of the force is 3000N
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