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anonymous

  • one year ago

What net force is required to bring a 1500 kg car to rest from a speed of 108 km/h in 15 s?

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  1. anonymous
    • one year ago
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    108km/h/3600s=0.03km/s=30m/s 0=0.03km/s+15s*(a) -0.03/s=15s*(a) a=-0.03/15 a=0.002km/s^2=2m/s^2 also Where F is the force and m is the mass as well as a being the acceleration F=2m/s^2*1500kg=3000N

  2. anonymous
    • one year ago
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    Can someone verify this for me please

  3. anonymous
    • one year ago
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    I did the conversion from kilometers per hour to meters per second to comply with the rules of F=ma and then the rest consists of finding the acceleration and dividing with the correct mass to find the right answer .

  4. anonymous
    • one year ago
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    Overall my answer says I would need 3000N force to stop a truck weighing 1500kg from the velocity of 108km/h to rest within 15 seconds.

  5. anonymous
    • one year ago
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    Does that seem realistic overall or should I reconsider the solution thanks

  6. CGGURUMANJUNATH
    • one year ago
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    :)

  7. CGGURUMANJUNATH
    • one year ago
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    U R RIGHT !

  8. anonymous
    • one year ago
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    Are you sure?

  9. anonymous
    • one year ago
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    Well I can't question your authority so yeah I think soXD

  10. anonymous
    • one year ago
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    Thanks guys:)

  11. anonymous
    • one year ago
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    you are right but it should be \[F=-3000N\] The force is acting in opposite direction to the vehicle, and this shows the retarding nature of the force the absolute value of the force is 3000N

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