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108km/h/3600s=0.03km/s=30m/s 0=0.03km/s+15s*(a) -0.03/s=15s*(a) a=-0.03/15 a=0.002km/s^2=2m/s^2 also Where F is the force and m is the mass as well as a being the acceleration F=2m/s^2*1500kg=3000N
Can someone verify this for me please
I did the conversion from kilometers per hour to meters per second to comply with the rules of F=ma and then the rest consists of finding the acceleration and dividing with the correct mass to find the right answer .
Overall my answer says I would need 3000N force to stop a truck weighing 1500kg from the velocity of 108km/h to rest within 15 seconds.
Does that seem realistic overall or should I reconsider the solution thanks
U R RIGHT !
Are you sure?
Well I can't question your authority so yeah I think soXD
you are right but it should be \[F=-3000N\] The force is acting in opposite direction to the vehicle, and this shows the retarding nature of the force the absolute value of the force is 3000N