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- anonymous

What net force is required to bring a 1500 kg car to rest from a speed of 108 km/h in 15 s?

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- anonymous

What net force is required to bring a 1500 kg car to rest from a speed of 108 km/h in 15 s?

- katieb

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- anonymous

108km/h/3600s=0.03km/s=30m/s
0=0.03km/s+15s*(a)
-0.03/s=15s*(a)
a=-0.03/15
a=0.002km/s^2=2m/s^2 also
Where F is the force and m is the mass as well as a being the acceleration
F=2m/s^2*1500kg=3000N

- anonymous

Can someone verify this for me please

- anonymous

I did the conversion from kilometers per hour to meters per second to comply with the rules of F=ma and then the rest consists of finding the acceleration and dividing with the correct mass to find the right answer .

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- anonymous

Overall my answer says I would need 3000N force to stop a truck weighing 1500kg from the velocity of 108km/h to rest within 15 seconds.

- anonymous

Does that seem realistic overall or should I reconsider the solution thanks

- CGGURUMANJUNATH

:)

- CGGURUMANJUNATH

U R RIGHT !

- anonymous

Are you sure?

- anonymous

Well I can't question your authority so yeah I think soXD

- anonymous

Thanks guys:)

- anonymous

you are right but it should be
\[F=-3000N\]
The force is acting in opposite direction to the vehicle, and this shows the retarding nature of the force
the absolute value of the force is 3000N

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