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mathmath333

  • one year ago

Counting problem

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{In how many ways can a student choose a programme } \hspace{.33em}\\~\\ & \normalsize \text{of 5 courses if 9 courses are available and 2 specific } \hspace{.33em}\\~\\ & \normalsize \text{courses are compulsory for every student.} \hspace{.33em}\\~\\ \end{align}}\)

  2. phi
    • one year ago
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    I assume order does not matter. we just want a list of 5 courses.

  3. mathmath333
    • one year ago
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    order doesn't matter.

  4. phi
    • one year ago
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    you have to choose the 2 required courses. that leaves 7 from which to pick 3 7 choose 3 right ?

  5. mathmath333
    • one year ago
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    yes

  6. phi
    • one year ago
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    and that is 35

  7. mathmath333
    • one year ago
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    u did \(^{7}C_{3}\) ,but what about the remaining \(2\) courses

  8. phi
    • one year ago
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    we could be pedantic and say 2C2 * 7C3

  9. mathmath333
    • one year ago
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    ok 2C2=1

  10. mathmath333
    • one year ago
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    answer is 35 ?

  11. phi
    • one year ago
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    yes. Make sense?

  12. mathmath333
    • one year ago
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    yes thnks

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spraguer (Moderator)
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