anonymous
  • anonymous
Multiply: 2 the square root of 11 • 8 the square root of 22 a. 8 the square root of 11 b. 10 the square root of 33 c. 64 the square root of 22 d. 176 the square root of 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Jack1
  • Jack1
\(\large 2\sqrt 11 \times 8\sqrt 22\)?
anonymous
  • anonymous
Yeah
anonymous
  • anonymous
I get to the point were it becomes 16 (sqrt) 242 then I dont know what to do

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Jack1
  • Jack1
sqrt 11 * sqrt 22 = sqrt 11 * sqrt 11 * sqrt 2 = (sqrt 11)^2 * sqrt 2 = 11 * sqrt 2
Jack1
  • Jack1
so now add in the x 2 and x 8
Jack1
  • Jack1
11 * 2 * 8 * sqrt 2 = 176 * sqrt 2
anonymous
  • anonymous
How did you get the sqrt 11 * sqrt 22
Jack1
  • Jack1
\(\Large 2\times \sqrt {11} \times 8 \times \sqrt {22}\) \(\Large 2\times 8 \times \sqrt {11} \times \sqrt {22}\) \(\Large 2\times 8 \times \sqrt {11} \times \sqrt {(2 \times 11)}\) \(\Large 2\times 8 \times \sqrt {11} \times \sqrt {2} \times \sqrt {11}\) \(\Large 2\times 8 \times \sqrt {11} \times \sqrt {11} \times \sqrt {2} \) \(\Large 2\times 8 \times 11 \times \sqrt {2} \)
anonymous
  • anonymous
Oh so you were just simplifying the equation?
Jack1
  • Jack1
yeps ;)
anonymous
  • anonymous
so that would be 176 (sqrt) 2
Jack1
  • Jack1
perfect
anonymous
  • anonymous
Thank you so much! It make so much more sense now
Jack1
  • Jack1
all good, np ;)

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