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anonymous

  • one year ago

Please help =*(

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  1. anonymous
    • one year ago
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    \[\frac{ x ^{36}-y ^{36} }{ (x ^{18}+y ^{18}) (x ^{9}+y ^{9}) }\]

  2. imqwerty
    • one year ago
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    a^2n - b^2n = (a^n + b^n) (a^n - b^n) try to apply this in the numerator

  3. anonymous
    • one year ago
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    so we don't FOIL in this case?

  4. anonymous
    • one year ago
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    just add the common values? the x's and y's?

  5. anonymous
    • one year ago
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    ?

  6. imqwerty
    • one year ago
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    FOIL method will be too long so you must try to factor the numerator and then cancel the common terms in the numerator nd denominator x^36-y^36 = (x^18-y^18)(x^18+y^18)

  7. anonymous
    • one year ago
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    hmmmm okay.... so tell me if this is right

  8. imqwerty
    • one year ago
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    So after splitting the numerator like this ^ can u see any terms cancelling??

  9. anonymous
    • one year ago
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    |dw:1439310575742:dw|

  10. anonymous
    • one year ago
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    can you do that with the denominator?

  11. imqwerty
    • one year ago
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    No

  12. anonymous
    • one year ago
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    but why not? Since they're multiply isnt it |dw:1439310745161:dw|

  13. imqwerty
    • one year ago
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    the denominator - (x^18+y^18)(x^9+y^9) =x^27 + (x^18)(y^9) + y^27 +(x^9)(y^18)

  14. anonymous
    • one year ago
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    So you're saying the denominator must be FOILed right?

  15. anonymous
    • one year ago
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    NOOOOOO i know what youre gonna say you're gonna say it's too long to FOIL but i'm just asking in general you cant add them like i asked previously because in these problems it has to be foiled right?

  16. imqwerty
    • one year ago
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    my method to solve the problem = we can write the numerator as - (x^36-y^36) = (x^18+y^18)(x^18-y^18) =(x^18+y^18)(x^9+y^9)(x^9-y^9) so now we plug this value of numerator in - (x^36-y^36)/[(x^18+y^18)(x^9+y^9)] so we have - [(x^18+y^18)(x^9+y^9)(x^9-y^9)]/[(x^18+y^18)(x^9+y^9)] after cancelling the common terms we have - x^9-y^9 as our answer

  17. anonymous
    • one year ago
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    I know how to do the problem I just need you to confirm what I asked.

  18. anonymous
    • one year ago
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    ?

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