anonymous
  • anonymous
Score Number of Students 0 2 1 1 2 3 3 6 4 2 5 3 6 2 Based on the table, what is the mean hockey score?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
i added them all up i got 19

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anonymous
  • anonymous
mean or average is total observations divided by number of observations or how frequent those observations are \[mean=\frac{0+1+2+3+4+5+6}{2+1+3+6+2+3+2}\]
anonymous
  • anonymous
7 over 19? @Nishant_Garg
anonymous
  • anonymous
anonymous
  • anonymous
doesn't look right
anonymous
  • anonymous
thats why i need help im confused
anonymous
  • anonymous
what is 1+2+3+4+5+6?
anonymous
  • anonymous
21
anonymous
  • anonymous
so 21/19
anonymous
  • anonymous
1.2
anonymous
  • anonymous
?
anonymous
  • anonymous
anonymous
  • anonymous
1.105
anonymous
  • anonymous
thats not a choice though....
anonymous
  • anonymous
anonymous
  • anonymous
do 0+0+1+2+2+2+3+3+3+3+3+3+4+4+5+5+5+6+6 DIVIDED BY
anonymous
  • anonymous
Divide that by 19
anonymous
  • anonymous
to get about 3.15
anonymous
  • anonymous
Is that an option?
anonymous
  • anonymous
@KAKES1967 Are you still there?
anonymous
  • anonymous
2.14
anonymous
  • anonymous
these are the options...2.7 2.9 3.2 5.2
anonymous
  • anonymous
2.7?
anonymous
  • anonymous
insteresting, one second
anonymous
  • anonymous
this is getting confusing
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
IrishBoy123
  • IrishBoy123
you need to weight the scores so \(\large \frac{2*0 + 1*1 + 3*2 + ...}{2 + 1 + 3...}\)
anonymous
  • anonymous
7 over 6
anonymous
  • anonymous
IrishBoy123
  • IrishBoy123
you need to complete that calculation i started. i included the first 3 numbers, include the remaining 4 in exactly the same way; and you will get there

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