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anonymous

  • one year ago

For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range. The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≤ 2.

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  1. anonymous
    • one year ago
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    correct answer gets medal and fan

  2. anonymous
    • one year ago
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    @Robert136

  3. anonymous
    • one year ago
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    @ali2x2

  4. anonymous
    • one year ago
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    @heretohelpalways

  5. anonymous
    • one year ago
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    @taramgrant0543664

  6. jigglypuff314
    • one year ago
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    Hi there :) Sorry for being a little late to respond .-. they have given you the equation in "vertex form" where \( f(x) = a(x-h)^2+k \) where the point \( (h,~k) \) is the vertex comparing this "form" to your \( f(x) = 3(x-1)^2 + 2 \) we can see that \( h=1 \) and \(k=2\) putting this as a point \((h,k)\), you would get the proper vertex point that they are asking for :)

  7. jigglypuff314
    • one year ago
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    The other deciding factor in your options, it seems, would be the range. If you have seen a picture of a \(parabola\) before [it looks like a U] from this we can say that anything above the vertex (in this case) would be included in the range so since we got that the y value of the vertex to be \(k=2\) we can say that the range of this function would be greater than and including \(2\)

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