itsmichelle29
  • itsmichelle29
Simplify root(1-sintheta)(1+sintheta)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\sqrt{(1-sin{\theta})(1+sin{\theta})}\] ?
anonymous
  • anonymous
Is that what you meant?
itsmichelle29
  • itsmichelle29
Yup

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More answers

itsmichelle29
  • itsmichelle29
±sin θ cos θ ±tan θ square root sine theta
itsmichelle29
  • itsmichelle29
those are the answerscan u help me
anonymous
  • anonymous
\(\sqrt{(1-sin{\theta})(1+sin{\theta})}\) \(\sqrt{(1-sin^2{\theta })}\) But \(cos^2{\theta} + sin^2{\theta} = 1\), then \(\sqrt{cos^2{\theta}}\) \(\pm cos{\theta}\)
itsmichelle29
  • itsmichelle29
so would the answer be costheta only
anonymous
  • anonymous
yes
itsmichelle29
  • itsmichelle29
omg thank you can u help me with one more only
anonymous
  • anonymous
sure^^
itsmichelle29
  • itsmichelle29
1 Attachment
itsmichelle29
  • itsmichelle29
@M4thM1nd
anonymous
  • anonymous
\(cos(x-\pi/2) = sin(x)\) and \(sin(x - \pi/2)=-cos(x)\)
anonymous
  • anonymous
So, which one you think is the right answer?
itsmichelle29
  • itsmichelle29
1st one
itsmichelle29
  • itsmichelle29
i think ... idk
anonymous
  • anonymous
No. From the graph we see that f(x) at x = 0 is 0, that means f(x) is some function of sin(x), since sin(x) at x = 0 is 0
itsmichelle29
  • itsmichelle29
so the answer is a
anonymous
  • anonymous
In that case, the first one we have \(sin(x-\pi/2) = -cos(x)\), so that can't be the right answer
itsmichelle29
  • itsmichelle29
okay the right answer is ...
anonymous
  • anonymous
If we check the last option, we have \(cos(x-\pi/2) = sin(x)\), but from the graph we also get the information that f(x) at x = pi/2 is equal to -4. But sin(x) at x = pi/2 is equal to 1. That tells us that we need a -4 multiplying this sin(x). So... The last option is the correct answer
anonymous
  • anonymous
do you understand?

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