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anonymous

  • one year ago

Help!!!!!!!

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  1. anonymous
    • one year ago
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    Identify the number that does not belong with the other three. Explain your reasoning. 50.1 repeating 1, negative 50 over 2, negative 50.1, square root 50

  2. anonymous
    • one year ago
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    @confluxepic Help!!!!!

  3. anonymous
    • one year ago
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    @ParthKohli please help

  4. anonymous
    • one year ago
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    @whpalmer4 please help

  5. anonymous
    • one year ago
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    @Michele_Laino

  6. anonymous
    • one year ago
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    @Michele_Laino please help

  7. anonymous
    • one year ago
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    @Michele_Laino

  8. Astrophysics
    • one year ago
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    The one that isn't rational

  9. Astrophysics
    • one year ago
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    You would first assume -50/2 just because it's negative, but that is also a rational number, but one of the numbers here isn't rational...so what would the answer be?

  10. anonymous
    • one year ago
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    -50.1

  11. Michele_Laino
    • one year ago
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    hint: \[\Large 50.\overline 1 = \frac{{501 - 50}}{9}\]

  12. anonymous
    • one year ago
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    im confused

  13. Astrophysics
    • one year ago
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    Look up the definition for rational number

  14. Michele_Laino
    • one year ago
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    hint: we can write this \[\Large \begin{gathered} 50.\overline 1 = \frac{{501 - 50}}{9} = \frac{{451}}{9} \hfill \\ \hfill \\ - \frac{{50}}{2},\quad - 50.1 = - \frac{{501}}{{10}} \hfill \\ \end{gathered} \]

  15. Michele_Laino
    • one year ago
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    furthermore, we are not able to find a pair of integer numbers, say m, and n, such that: \[\Large \sqrt 2 = \frac{m}{n}\]

  16. anonymous
    • one year ago
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    i do not understand

  17. Michele_Laino
    • one year ago
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    oops.. \[\Large \sqrt {50} = \frac{m}{n}\]

  18. Michele_Laino
    • one year ago
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    in other words, the first three numbers can be expressed as ratios, whereas the fourth number, namely sqrt(50), can not be expressed as a ratio, so what can you conclude?

  19. anonymous
    • one year ago
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    square root 50 does not belong

  20. anonymous
    • one year ago
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    but why ? @Michele_Laino

  21. Michele_Laino
    • one year ago
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    because sqrt(50) we can not find a pair of integers, (m,n) such that: \[\Large \sqrt {50} = \frac{m}{n}\] in other words sqrt(50) is an irrational number, whereas the others three numbers are rational numbers, since they can be expressed as fractions

  22. Astrophysics
    • one year ago
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    Easily put, rational numbers are any number that can be made by dividing two integers, but \[\sqrt{50}\] can't be, same reason for pi, that is not a rational number,

  23. anonymous
    • one year ago
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    @Michele_Laino can you help me with two more

  24. Michele_Laino
    • one year ago
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    ok!

  25. anonymous
    • one year ago
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    Which mathematical symbol would best fill in the blank to compare the two real numbers? 7.6 repeating blank square root 55 < > = ≈

  26. anonymous
    • one year ago
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    @Michele_Laino

  27. Michele_Laino
    • one year ago
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    what do you mean with 7.6 repeating blank?

  28. anonymous
    • one year ago
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    \[7.6 ____ \sqrt{55}\]

  29. Michele_Laino
    • one year ago
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    do you mean 7.6?

  30. Michele_Laino
    • one year ago
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    if we make the square of the two numbers, we get this: \[\Large {7.6^2} = {\left( {\frac{{76}}{{10}}} \right)^2} > 55\] am I right?

  31. anonymous
    • one year ago
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    so it would be greater

  32. Michele_Laino
    • one year ago
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    yes! also between the starting numbers the same symbol holds

  33. anonymous
    • one year ago
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    which symbol is greater again?

  34. Michele_Laino
    • one year ago
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    the right symbol is: ">"

  35. Michele_Laino
    • one year ago
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    in general, if: \[\large {n^2} > {m^2}\] then: \[\Large n > m\]

  36. Michele_Laino
    • one year ago
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    where n and m are positive numbers

  37. anonymous
    • one year ago
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    yes

  38. anonymous
    • one year ago
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    Order the set of numbers from least to greatest: negative 5 over 6, negative 5, negative square root 26, negative 31 over 6 negative 31 over 6, negative square root 26, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative 31 over 6, negative square root 26 negative square root 26, negative 31 over 6, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative square root 26, negative 31 over 6

  39. Michele_Laino
    • one year ago
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    As before I consider the square of each number: \[\Large \begin{gathered} - \frac{5}{6} \to {\left( { - \frac{5}{6}} \right)^2} = \frac{{25}}{{36}} \hfill \\ \hfill \\ - 5 \to {\left( { - 5} \right)^2} = 25 = \frac{{900}}{{36}} \hfill \\ \hfill \\ - \sqrt {26} \to 26 = \frac{{936}}{{36}} \hfill \\ \hfill \\ - \frac{{31}}{6} \to {\left( { - \frac{{31}}{6}} \right)^2} = \frac{{961}}{{36}} \hfill \\ \end{gathered} \]

  40. anonymous
    • one year ago
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    can i say what my answer is

  41. Michele_Laino
    • one year ago
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    I'm sorry I can not say the answer directly, since it is against the Code of Conduct

  42. Michele_Laino
    • one year ago
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    please compare the square of those numbers

  43. Michele_Laino
    • one year ago
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    we have this drawing: |dw:1439319394062:dw|

  44. Michele_Laino
    • one year ago
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    am I right?

  45. Michele_Laino
    • one year ago
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    furthermore, you have to keep in mind that your numbers are negative, so the number which has the square bigger than others, is the first number in your sequence

  46. anonymous
    • one year ago
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    its the last answer -5/6 -5 - square 26 -31/6

  47. anonymous
    • one year ago
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    @Michele_Laino

  48. anonymous
    • one year ago
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    least to greatest

  49. Michele_Laino
    • one year ago
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    no, since -31/6 has the square bigger than others, so it is the first number of your sequence, so we have: -31/6,...

  50. anonymous
    • one year ago
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    so its A

  51. Michele_Laino
    • one year ago
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    the order is reversed, since your numbers are all negative numbers

  52. Michele_Laino
    • one year ago
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    yes! correct, it is option A

  53. anonymous
    • one year ago
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    thank your Michele (:

  54. Michele_Laino
    • one year ago
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    :)

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