Help!!!!!!!

- anonymous

Help!!!!!!!

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- schrodinger

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- anonymous

Identify the number that does not belong with the other three. Explain your reasoning. 50.1 repeating 1, negative 50 over 2, negative 50.1, square root 50

- anonymous

@confluxepic Help!!!!!

- anonymous

@ParthKohli please help

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## More answers

- anonymous

@whpalmer4 please help

- anonymous

@Michele_Laino

- anonymous

@Michele_Laino please help

- anonymous

@Michele_Laino

- Astrophysics

The one that isn't rational

- Astrophysics

You would first assume -50/2 just because it's negative, but that is also a rational number, but one of the numbers here isn't rational...so what would the answer be?

- anonymous

-50.1

- Michele_Laino

hint:
\[\Large 50.\overline 1 = \frac{{501 - 50}}{9}\]

- anonymous

im confused

- Astrophysics

Look up the definition for rational number

- Michele_Laino

hint:
we can write this
\[\Large \begin{gathered}
50.\overline 1 = \frac{{501 - 50}}{9} = \frac{{451}}{9} \hfill \\
\hfill \\
- \frac{{50}}{2},\quad - 50.1 = - \frac{{501}}{{10}} \hfill \\
\end{gathered} \]

- Michele_Laino

furthermore, we are not able to find a pair of integer numbers, say m, and n, such that:
\[\Large \sqrt 2 = \frac{m}{n}\]

- anonymous

i do not understand

- Michele_Laino

oops..
\[\Large \sqrt {50} = \frac{m}{n}\]

- Michele_Laino

in other words, the first three numbers can be expressed as ratios, whereas the fourth number, namely sqrt(50), can not be expressed as a ratio, so what can you conclude?

- anonymous

square root 50 does not belong

- anonymous

but why ? @Michele_Laino

- Michele_Laino

because sqrt(50) we can not find a pair of integers, (m,n) such that:
\[\Large \sqrt {50} = \frac{m}{n}\]
in other words sqrt(50) is an irrational number, whereas the others three numbers are rational numbers, since they can be expressed as fractions

- Astrophysics

Easily put, rational numbers are any number that can be made by dividing two integers, but \[\sqrt{50}\] can't be, same reason for pi, that is not a rational number,

- anonymous

@Michele_Laino can you help me with two more

- Michele_Laino

ok!

- anonymous

Which mathematical symbol would best fill in the blank to compare the two real numbers?
7.6 repeating blank square root 55
<
>
=
â‰ˆ

- anonymous

@Michele_Laino

- Michele_Laino

what do you mean with 7.6 repeating blank?

- anonymous

\[7.6 ____ \sqrt{55}\]

- Michele_Laino

do you mean 7.6?

- Michele_Laino

if we make the square of the two numbers, we get this:
\[\Large {7.6^2} = {\left( {\frac{{76}}{{10}}} \right)^2} > 55\]
am I right?

- anonymous

so it would be greater

- Michele_Laino

yes! also between the starting numbers the same symbol holds

- anonymous

which symbol is greater again?

- Michele_Laino

the right symbol is: ">"

- Michele_Laino

in general, if:
\[\large {n^2} > {m^2}\]
then:
\[\Large n > m\]

- Michele_Laino

where n and m are positive numbers

- anonymous

yes

- anonymous

Order the set of numbers from least to greatest: negative 5 over 6, negative 5, negative square root 26, negative 31 over 6
negative 31 over 6, negative square root 26, negative 5, negative 5 over 6
negative 5 over 6, negative 5, negative 31 over 6, negative square root 26
negative square root 26, negative 31 over 6, negative 5, negative 5 over 6
negative 5 over 6, negative 5, negative square root 26, negative 31 over 6

- Michele_Laino

As before I consider the square of each number:
\[\Large \begin{gathered}
- \frac{5}{6} \to {\left( { - \frac{5}{6}} \right)^2} = \frac{{25}}{{36}} \hfill \\
\hfill \\
- 5 \to {\left( { - 5} \right)^2} = 25 = \frac{{900}}{{36}} \hfill \\
\hfill \\
- \sqrt {26} \to 26 = \frac{{936}}{{36}} \hfill \\
\hfill \\
- \frac{{31}}{6} \to {\left( { - \frac{{31}}{6}} \right)^2} = \frac{{961}}{{36}} \hfill \\
\end{gathered} \]

- anonymous

can i say what my answer is

- Michele_Laino

I'm sorry I can not say the answer directly, since it is against the Code of Conduct

- Michele_Laino

please compare the square of those numbers

- Michele_Laino

we have this drawing:
|dw:1439319394062:dw|

- Michele_Laino

am I right?

- Michele_Laino

furthermore, you have to keep in mind that your numbers are negative, so the number which has the square bigger than others, is the first number in your sequence

- anonymous

its the last answer -5/6 -5 - square 26 -31/6

- anonymous

@Michele_Laino

- anonymous

least to greatest

- Michele_Laino

no, since -31/6 has the square bigger than others, so it is the first number of your sequence, so we have:
-31/6,...

- anonymous

so its A

- Michele_Laino

the order is reversed, since your numbers are all negative numbers

- Michele_Laino

yes! correct, it is option A

- anonymous

thank your Michele (:

- Michele_Laino

:)

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