anonymous
  • anonymous
Help!!!!!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Identify the number that does not belong with the other three. Explain your reasoning. 50.1 repeating 1, negative 50 over 2, negative 50.1, square root 50
anonymous
  • anonymous
@confluxepic Help!!!!!
anonymous
  • anonymous
@ParthKohli please help

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More answers

anonymous
  • anonymous
@whpalmer4 please help
anonymous
  • anonymous
@Michele_Laino
anonymous
  • anonymous
@Michele_Laino please help
anonymous
  • anonymous
@Michele_Laino
Astrophysics
  • Astrophysics
The one that isn't rational
Astrophysics
  • Astrophysics
You would first assume -50/2 just because it's negative, but that is also a rational number, but one of the numbers here isn't rational...so what would the answer be?
anonymous
  • anonymous
-50.1
Michele_Laino
  • Michele_Laino
hint: \[\Large 50.\overline 1 = \frac{{501 - 50}}{9}\]
anonymous
  • anonymous
im confused
Astrophysics
  • Astrophysics
Look up the definition for rational number
Michele_Laino
  • Michele_Laino
hint: we can write this \[\Large \begin{gathered} 50.\overline 1 = \frac{{501 - 50}}{9} = \frac{{451}}{9} \hfill \\ \hfill \\ - \frac{{50}}{2},\quad - 50.1 = - \frac{{501}}{{10}} \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
furthermore, we are not able to find a pair of integer numbers, say m, and n, such that: \[\Large \sqrt 2 = \frac{m}{n}\]
anonymous
  • anonymous
i do not understand
Michele_Laino
  • Michele_Laino
oops.. \[\Large \sqrt {50} = \frac{m}{n}\]
Michele_Laino
  • Michele_Laino
in other words, the first three numbers can be expressed as ratios, whereas the fourth number, namely sqrt(50), can not be expressed as a ratio, so what can you conclude?
anonymous
  • anonymous
square root 50 does not belong
anonymous
  • anonymous
but why ? @Michele_Laino
Michele_Laino
  • Michele_Laino
because sqrt(50) we can not find a pair of integers, (m,n) such that: \[\Large \sqrt {50} = \frac{m}{n}\] in other words sqrt(50) is an irrational number, whereas the others three numbers are rational numbers, since they can be expressed as fractions
Astrophysics
  • Astrophysics
Easily put, rational numbers are any number that can be made by dividing two integers, but \[\sqrt{50}\] can't be, same reason for pi, that is not a rational number,
anonymous
  • anonymous
@Michele_Laino can you help me with two more
Michele_Laino
  • Michele_Laino
ok!
anonymous
  • anonymous
Which mathematical symbol would best fill in the blank to compare the two real numbers? 7.6 repeating blank square root 55 < > = ≈
anonymous
  • anonymous
@Michele_Laino
Michele_Laino
  • Michele_Laino
what do you mean with 7.6 repeating blank?
anonymous
  • anonymous
\[7.6 ____ \sqrt{55}\]
Michele_Laino
  • Michele_Laino
do you mean 7.6?
Michele_Laino
  • Michele_Laino
if we make the square of the two numbers, we get this: \[\Large {7.6^2} = {\left( {\frac{{76}}{{10}}} \right)^2} > 55\] am I right?
anonymous
  • anonymous
so it would be greater
Michele_Laino
  • Michele_Laino
yes! also between the starting numbers the same symbol holds
anonymous
  • anonymous
which symbol is greater again?
Michele_Laino
  • Michele_Laino
the right symbol is: ">"
Michele_Laino
  • Michele_Laino
in general, if: \[\large {n^2} > {m^2}\] then: \[\Large n > m\]
Michele_Laino
  • Michele_Laino
where n and m are positive numbers
anonymous
  • anonymous
yes
anonymous
  • anonymous
Order the set of numbers from least to greatest: negative 5 over 6, negative 5, negative square root 26, negative 31 over 6 negative 31 over 6, negative square root 26, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative 31 over 6, negative square root 26 negative square root 26, negative 31 over 6, negative 5, negative 5 over 6 negative 5 over 6, negative 5, negative square root 26, negative 31 over 6
Michele_Laino
  • Michele_Laino
As before I consider the square of each number: \[\Large \begin{gathered} - \frac{5}{6} \to {\left( { - \frac{5}{6}} \right)^2} = \frac{{25}}{{36}} \hfill \\ \hfill \\ - 5 \to {\left( { - 5} \right)^2} = 25 = \frac{{900}}{{36}} \hfill \\ \hfill \\ - \sqrt {26} \to 26 = \frac{{936}}{{36}} \hfill \\ \hfill \\ - \frac{{31}}{6} \to {\left( { - \frac{{31}}{6}} \right)^2} = \frac{{961}}{{36}} \hfill \\ \end{gathered} \]
anonymous
  • anonymous
can i say what my answer is
Michele_Laino
  • Michele_Laino
I'm sorry I can not say the answer directly, since it is against the Code of Conduct
Michele_Laino
  • Michele_Laino
please compare the square of those numbers
Michele_Laino
  • Michele_Laino
we have this drawing: |dw:1439319394062:dw|
Michele_Laino
  • Michele_Laino
am I right?
Michele_Laino
  • Michele_Laino
furthermore, you have to keep in mind that your numbers are negative, so the number which has the square bigger than others, is the first number in your sequence
anonymous
  • anonymous
its the last answer -5/6 -5 - square 26 -31/6
anonymous
  • anonymous
@Michele_Laino
anonymous
  • anonymous
least to greatest
Michele_Laino
  • Michele_Laino
no, since -31/6 has the square bigger than others, so it is the first number of your sequence, so we have: -31/6,...
anonymous
  • anonymous
so its A
Michele_Laino
  • Michele_Laino
the order is reversed, since your numbers are all negative numbers
Michele_Laino
  • Michele_Laino
yes! correct, it is option A
anonymous
  • anonymous
thank your Michele (:
Michele_Laino
  • Michele_Laino
:)

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