## calculusxy one year ago MEDAL!!! Represent the area of a triangle with a base of 2x + y and a height of 4z. A. 2z(2x + y) B. 2x( z + y) C. 2xyz D. x(2x + y) E. 2z + 4xy

1. imqwerty

area of triangle = 1/2 x base x height

2. Astrophysics

Hint: $A_{\triangle}=\frac{ 1 }{ 2 }bh$

3. Astrophysics

qwerty@!@@#@#

4. imqwerty

:D lol

5. Astrophysics

haha

6. calculusxy

I know that.

7. calculusxy

But I was thinking about substituting the variables for some numbers.

8. imqwerty

base =2x+y height =4z

9. Astrophysics

$A = \frac{ 1 }{ 2 }(4z)(2x+y)$

10. Astrophysics

Simplify, all you had to do was plug it in

11. imqwerty

A=2z(2x+y)

12. imqwerty

do u wan the solution to that quadrilateral question @Astrophysics ??

13. Astrophysics

YES

14. imqwerty

ok

15. imqwerty

lemme solve it XD

16. calculusxy

So why did it only cancel out the 4 and not the 2. was it to only find half of from only one part (or one number).

17. imqwerty

ok can u tell what is 2+1??

18. imqwerty

m not kiddin okay answer this^

19. MrNood

it is half base times height OR half height times base half height = 4z/2 = 2z

20. phi

it works the same as $\frac{1}{2} \cdot 4 \cdot 8$ you can group it like this $\left(\frac{1}{2} \cdot 4 \right) \cdot 8$ only the 4 *1/2 is simplified to 2 and you get 2*8 or 16 if 8 were something complicated like (x+2y) it still be $\left(\frac{1}{2} \cdot 4 \right) \cdot (x+2y)$

21. imqwerty

we know that 2+1 = 3 nd if we find out (2+1)/2 then we can't cancel out 2 :) if u cancell it out then ur left with 1 but we know that 2+1 = 3 nd 3/2 is not 1. so u can't divide like that