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anonymous
 one year ago
if v1=(2,5) and v2=(4,3) then the angle between the two vectors is_____ degrees. (Round your answer to two decimal places)
anonymous
 one year ago
if v1=(2,5) and v2=(4,3) then the angle between the two vectors is_____ degrees. (Round your answer to two decimal places)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Hero can you help me?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1that's part of the process but where did you get minus sign?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well when you add8 and 15, you get 23, or did I do it wrong?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.18 and  15?? same again, where are the signs coming from ?!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what I did was (2)(4)+(5)(3) and that is how I 23

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\(\vec a \bullet \vec b = <a_{x}, a_{y}>\bullet <b_{x},b_{y}> = a_{x}*b_{x}+a_{y}*b_{y}\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1you have \(\vec v_1=(2,5)\) and \( \vec v_2=(4,3)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually they are (2,5) and v2=(4,3),

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1can you just check that again because you posted differently above...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh never mind, I am going stupid, sorry about that, I got mixed up!

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1so is the opening post right, then?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1or is it (2,5) and v2=(4,3) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah the opening post is that right one, soory again!

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1so the dot prod is 23, right?!?! next, the dot product is also this: \(\vec a \bullet \vec b = \vec a  \  \vec b \ cos \theta\), right? so you need \( \vec a \) and \( \vec b\)....

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\(\vec a = \sqrt {a_x^2 + a_y ^2}\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1do that for v1, and v2

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1and then \(\large \theta = cos^{1}( \frac {23}{\vec v_1 \ \vec v_2})\) gotta dash...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is hard i am getting really confused!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait for v1 and v2 in the bottom of the equation, what do i sub them in for?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1i showed you above how to calc \(\vec a\), which is the magnitude of \(\vec a\) you do that for v1 and v2 then put them into the equation i'll do v1 \( \vec v_1 = \sqrt { 2^2 + (5)^2} = \sqrt{4 + 25} = \sqrt {29}\) can you do the same for v2?
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