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anonymous

  • one year ago

solve this equation for x and round to the nearest 100th 1=In(x+4)

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  1. welshfella
    • one year ago
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    x + 4 = e^1 = e

  2. welshfella
    • one year ago
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    solve for x

  3. anonymous
    • one year ago
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    -4?

  4. welshfella
    • one year ago
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    no x + 4 = e not 0

  5. anonymous
    • one year ago
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    -1.28

  6. welshfella
    • one year ago
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    ln means log to the base e you can find the value of e on your calculator

  7. anonymous
    • one year ago
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    i used it

  8. welshfella
    • one year ago
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    looks good

  9. welshfella
    • one year ago
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    recall what logs are |dw:1439319631515:dw|

  10. anonymous
    • one year ago
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    it won't let me type the neg so i don't think it is neg

  11. welshfella
    • one year ago
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    the log is an exponent

  12. anonymous
    • one year ago
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    I'm confused on how to set it up

  13. welshfella
    • one year ago
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    try practicing a few similar problems

  14. welshfella
    • one year ago
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    like ;- transform to exponent form log10 100 = 2 answer 10^2 = 100

  15. anonymous
    • one year ago
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    okay i understand that one

  16. anonymous
    • one year ago
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    i think I'm just overthinking this

  17. welshfella
    • one year ago
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    maybe remember that the log is the exponent and the base is the value that the goes 'under' the exponent

  18. welshfella
    • one year ago
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    |dw:1439320224760:dw|

  19. anonymous
    • one year ago
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    okay i get it kinda

  20. welshfella
    • one year ago
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    yea with practice you will if a get confused i write the log10 reelation then compare it with the one in the problem log10 100 = 2 wand know that 100 = 10^2

  21. anonymous
    • one year ago
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    okay yeah i get that part

  22. welshfella
    • one year ago
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    so if we have ln(x + 1) = 1 e relates to 10 , x + 1 relates to 100 and 1 relates to 2

  23. welshfella
    • one year ago
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    remember that ln = log to the base e

  24. anonymous
    • one year ago
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    but idk where your getting the e at

  25. anonymous
    • one year ago
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  26. anonymous
    • one year ago
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    so e^in(x+4)=e^1

  27. anonymous
    • one year ago
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    i got a neg number

  28. anonymous
    • one year ago
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    -1.28

  29. freckles
    • one year ago
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    that is right to the hundredths place ln is the same as log_e so the equation you had could have been written as: \[1=\log_e(x+4) \\ e^1=x+4 \text{ is the same equation in exponential form } \\ e=x+4 \\ \] and yes subtracting 4 on both sides gives you x is approximately -1.28

  30. anonymous
    • one year ago
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    it said it was wrong

  31. freckles
    • one year ago
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    -1.28 is right

  32. freckles
    • one year ago
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    the equation you typed was 1=ln(x+4) which does imply to the 100ths x=-1.28

  33. anonymous
    • one year ago
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    my school said that is was wrong..

  34. welshfella
    • one year ago
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    well your school is wrong

  35. welshfella
    • one year ago
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    are you sure your question is correct?

  36. freckles
    • one year ago
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    or the equation he typed is not the equation he should have typed

  37. welshfella
    • one year ago
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    yes

  38. freckles
    • one year ago
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    or... there is one other or but very unlikely the meaning of ln in most subjects mean log base e maybe ln means log base 2 because he is in computer science :p

  39. welshfella
    • one year ago
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    oh - i've never seen ln defined that way..

  40. anonymous
    • one year ago
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    pleaseeeeeeeeeeeeee come to my question! :) @welshfella

  41. anonymous
    • one year ago
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    i copied and pasted and we even used the right formula and everything

  42. freckles
    • one year ago
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    sometimes copy and paste doesn't work out so smoothly because you copying and pasting from a format that doesn't always translate over smoothly

  43. freckles
    • one year ago
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    the equation looks exactly like 1=ln(x+4) ?

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