anonymous
  • anonymous
Solve 2x2 − 8x = −7. negative 2 plus or minus square root of 2 negative 2 plus or minus 2 square root of 2 quantity of 2 plus or minus square root of 2 all over 2 2 plus or minus square root of 2 end root over 2
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
correct answer will get medal and fan
anonymous
  • anonymous
Nnesha
  • Nnesha
set it equal to zero

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Nnesha
  • Nnesha
then use quadratic\[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] formula a b and c are \[\large\rm Ax^2+Bx+C=0\] a=leading coefficient b=middle term c=constant term
anonymous
  • anonymous
a=3,b=−7,c=3
anonymous
  • anonymous
Nnesha
  • Nnesha
bo
Nnesha
  • Nnesha
\[2x^2-8x=-7\] first set it equal to zero write it in Ax^2+Bx+C=0 form add 7 both sides
anonymous
  • anonymous
so b is correct @Nnesha
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha bo \(\color{blue}{\text{End of Quote}}\) correction no
Nnesha
  • Nnesha
add 7 both sides let me know what you get
anonymous
  • anonymous
4 ± 2√ 2
anonymous
  • anonymous
but thats not an answer choice @Nnesha
Nnesha
  • Nnesha
that should be in fraction form
Nnesha
  • Nnesha
a= ?? there is 2a at the denominator replace a by its value and multiply that with 2
Nnesha
  • Nnesha
check your equation is there a typo somwhere ?

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