## anonymous one year ago Solve 2x2 − 8x = −7. negative 2 plus or minus square root of 2 negative 2 plus or minus 2 square root of 2 quantity of 2 plus or minus square root of 2 all over 2 2 plus or minus square root of 2 end root over 2

1. anonymous

correct answer will get medal and fan

2. anonymous

@aaronq @Nnesha

3. Nnesha

set it equal to zero

4. Nnesha

then use quadratic$\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$ formula a b and c are $\large\rm Ax^2+Bx+C=0$ a=leading coefficient b=middle term c=constant term

5. anonymous

a=3,b=−7,c=3

6. anonymous

@Nnesha

7. Nnesha

bo

8. Nnesha

$2x^2-8x=-7$ first set it equal to zero write it in Ax^2+Bx+C=0 form add 7 both sides

9. anonymous

so b is correct @Nnesha

10. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha bo $$\color{blue}{\text{End of Quote}}$$ correction no

11. Nnesha

add 7 both sides let me know what you get

12. anonymous

4 ± 2√ 2

13. anonymous

but thats not an answer choice @Nnesha

14. Nnesha

that should be in fraction form

15. Nnesha

a= ?? there is 2a at the denominator replace a by its value and multiply that with 2

16. Nnesha

check your equation is there a typo somwhere ?