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anonymous

  • one year ago

Solve 2x2 − 8x = −7. negative 2 plus or minus square root of 2 negative 2 plus or minus 2 square root of 2 quantity of 2 plus or minus square root of 2 all over 2 2 plus or minus square root of 2 end root over 2

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  1. anonymous
    • one year ago
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    correct answer will get medal and fan

  2. anonymous
    • one year ago
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    @aaronq @Nnesha

  3. Nnesha
    • one year ago
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    set it equal to zero

  4. Nnesha
    • one year ago
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    then use quadratic\[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] formula a b and c are \[\large\rm Ax^2+Bx+C=0\] a=leading coefficient b=middle term c=constant term

  5. anonymous
    • one year ago
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    a=3,b=−7,c=3

  6. anonymous
    • one year ago
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    @Nnesha

  7. Nnesha
    • one year ago
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    bo

  8. Nnesha
    • one year ago
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    \[2x^2-8x=-7\] first set it equal to zero write it in Ax^2+Bx+C=0 form add 7 both sides

  9. anonymous
    • one year ago
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    so b is correct @Nnesha

  10. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha bo \(\color{blue}{\text{End of Quote}}\) correction no

  11. Nnesha
    • one year ago
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    add 7 both sides let me know what you get

  12. anonymous
    • one year ago
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    4 ± 2√ 2

  13. anonymous
    • one year ago
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    but thats not an answer choice @Nnesha

  14. Nnesha
    • one year ago
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    that should be in fraction form

  15. Nnesha
    • one year ago
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    a= ?? there is 2a at the denominator replace a by its value and multiply that with 2

  16. Nnesha
    • one year ago
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    check your equation is there a typo somwhere ?

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