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anonymous

  • one year ago

Solve the following system of equations and show all work. y = −x2 + 4 y = 2x + 1

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  1. anonymous
    • one year ago
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    @Preetha

  2. anonymous
    • one year ago
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    @ganeshie8

  3. anonymous
    • one year ago
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    I know the answers i just need help with how to get there

  4. anonymous
    • one year ago
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    @Hero

  5. anonymous
    • one year ago
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    @Shalante any ideas??

  6. anonymous
    • one year ago
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    \[x^2\] is x^2 not x2

  7. anonymous
    • one year ago
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    yes, sorry it copy and pasted wrong

  8. anonymous
    • one year ago
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    if y=-x^2+4 and y=2x+1 then -x^2+4=2x+1 Know how to solve for x?

  9. anonymous
    • one year ago
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    not really lol

  10. anonymous
    • one year ago
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    if you do know how to solve for x, plug the x value to any of the equation to get y

  11. anonymous
    • one year ago
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    we don't know the x value

  12. anonymous
    • one year ago
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    \[-x^2+4=2x+1\]

  13. anonymous
    • one year ago
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    so solve and that is the solution?

  14. anonymous
    • one year ago
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    \[x^2+2x-3\] move it over

  15. anonymous
    • one year ago
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    yes you know how to solve that?

  16. anonymous
    • one year ago
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    there should be two solutions with both having (x,y) form

  17. anonymous
    • one year ago
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    what is the first step to solve that? lost again

  18. anonymous
    • one year ago
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    where do i go after the x^2+2x-3

  19. anonymous
    • one year ago
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    factor it ( )( )

  20. anonymous
    • one year ago
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    (x-1) (x+3) ? sorry I'm confused

  21. anonymous
    • one year ago
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    ?

  22. anonymous
    • one year ago
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    Yea you are right.

  23. anonymous
    • one year ago
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    then what?

  24. anonymous
    • one year ago
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    oops

  25. anonymous
    • one year ago
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    dunno why it took me back to my old reply

  26. anonymous
    • one year ago
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    forgot to tell you its \[x^2+2x-3=0\]

  27. anonymous
    • one year ago
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    so quadratic ?

  28. anonymous
    • one year ago
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    that is what happens when you move all the numbers to the other side of an equation. After everything is gone, you a zero to it.

  29. anonymous
    • one year ago
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    yes i know

  30. anonymous
    • one year ago
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    so you get -3 after solving

  31. anonymous
    • one year ago
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    and 1

  32. anonymous
    • one year ago
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    so those are the x's what about the y's??

  33. anonymous
    • one year ago
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    Then plug both this x back into the first 2 equation using both x=-3 and x=1

  34. anonymous
    • one year ago
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    they should both equal right?

  35. anonymous
    • one year ago
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    yes they both get -5

  36. anonymous
    • one year ago
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    ANSWER #1 (x,y) plug in first x ANSWER #2 (x,y) plug in second x

  37. anonymous
    • one year ago
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    oops my orignial was wrong hold on

  38. anonymous
    • one year ago
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    so answer #1 is (-3,-5). you are correct on first one.

  39. anonymous
    • one year ago
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    I got everything under control! thanks so much!

  40. anonymous
    • one year ago
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    Yea, no problem.

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