anonymous
  • anonymous
Solve the following system of equations and show all work. y = −x2 + 4 y = 2x + 1
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@Preetha
anonymous
  • anonymous
@ganeshie8
anonymous
  • anonymous
I know the answers i just need help with how to get there

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@Hero
anonymous
  • anonymous
@Shalante any ideas??
anonymous
  • anonymous
\[x^2\] is x^2 not x2
anonymous
  • anonymous
yes, sorry it copy and pasted wrong
anonymous
  • anonymous
if y=-x^2+4 and y=2x+1 then -x^2+4=2x+1 Know how to solve for x?
anonymous
  • anonymous
not really lol
anonymous
  • anonymous
if you do know how to solve for x, plug the x value to any of the equation to get y
anonymous
  • anonymous
we don't know the x value
anonymous
  • anonymous
\[-x^2+4=2x+1\]
anonymous
  • anonymous
so solve and that is the solution?
anonymous
  • anonymous
\[x^2+2x-3\] move it over
anonymous
  • anonymous
yes you know how to solve that?
anonymous
  • anonymous
there should be two solutions with both having (x,y) form
anonymous
  • anonymous
what is the first step to solve that? lost again
anonymous
  • anonymous
where do i go after the x^2+2x-3
anonymous
  • anonymous
factor it ( )( )
anonymous
  • anonymous
(x-1) (x+3) ? sorry I'm confused
anonymous
  • anonymous
?
anonymous
  • anonymous
Yea you are right.
anonymous
  • anonymous
then what?
anonymous
  • anonymous
oops
anonymous
  • anonymous
dunno why it took me back to my old reply
anonymous
  • anonymous
forgot to tell you its \[x^2+2x-3=0\]
anonymous
  • anonymous
so quadratic ?
anonymous
  • anonymous
that is what happens when you move all the numbers to the other side of an equation. After everything is gone, you a zero to it.
anonymous
  • anonymous
yes i know
anonymous
  • anonymous
so you get -3 after solving
anonymous
  • anonymous
and 1
anonymous
  • anonymous
so those are the x's what about the y's??
anonymous
  • anonymous
Then plug both this x back into the first 2 equation using both x=-3 and x=1
anonymous
  • anonymous
they should both equal right?
anonymous
  • anonymous
yes they both get -5
anonymous
  • anonymous
ANSWER #1 (x,y) plug in first x ANSWER #2 (x,y) plug in second x
anonymous
  • anonymous
oops my orignial was wrong hold on
anonymous
  • anonymous
so answer #1 is (-3,-5). you are correct on first one.
anonymous
  • anonymous
I got everything under control! thanks so much!
anonymous
  • anonymous
Yea, no problem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.