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anonymous
 one year ago
Solve the following system of equations and show all work.
y = −x2 + 4
y = 2x + 1
anonymous
 one year ago
Solve the following system of equations and show all work. y = −x2 + 4 y = 2x + 1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know the answers i just need help with how to get there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Shalante any ideas??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2\] is x^2 not x2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, sorry it copy and pasted wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if y=x^2+4 and y=2x+1 then x^2+4=2x+1 Know how to solve for x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you do know how to solve for x, plug the x value to any of the equation to get y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we don't know the x value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so solve and that is the solution?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2+2x3\] move it over

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes you know how to solve that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there should be two solutions with both having (x,y) form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what is the first step to solve that? lost again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where do i go after the x^2+2x3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x1) (x+3) ? sorry I'm confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dunno why it took me back to my old reply

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0forgot to tell you its \[x^2+2x3=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is what happens when you move all the numbers to the other side of an equation. After everything is gone, you a zero to it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you get 3 after solving

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so those are the x's what about the y's??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then plug both this x back into the first 2 equation using both x=3 and x=1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they should both equal right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes they both get 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ANSWER #1 (x,y) plug in first x ANSWER #2 (x,y) plug in second x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops my orignial was wrong hold on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so answer #1 is (3,5). you are correct on first one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got everything under control! thanks so much!
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