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I know the answers i just need help with how to get there

\[x^2\] is x^2 not x2

yes, sorry it copy and pasted wrong

if y=-x^2+4
and y=2x+1
then -x^2+4=2x+1
Know how to solve for x?

not really lol

if you do know how to solve for x, plug the x value to any of the equation to get y

we don't know the x value

\[-x^2+4=2x+1\]

so solve and that is the solution?

\[x^2+2x-3\]
move it over

yes you know how to solve that?

there should be two solutions with both having (x,y) form

what is the first step to solve that? lost again

where do i go after the x^2+2x-3

factor it ( )( )

(x-1) (x+3) ?
sorry I'm confused

Yea you are right.

then what?

oops

dunno why it took me back to my old reply

forgot to tell you its
\[x^2+2x-3=0\]

so quadratic ?

yes i know

so you get -3 after solving

and 1

so those are the x's what about the y's??

Then plug both this x back into the first 2 equation using both x=-3 and x=1

they should both equal right?

yes they both get -5

ANSWER #1 (x,y) plug in first x
ANSWER #2 (x,y) plug in second x

oops my orignial was wrong hold on

so answer #1 is (-3,-5). you are correct on first one.

I got everything under control! thanks so much!

Yea, no problem.