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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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let cos theta = x so replace all cos with x \[\huge\rm (x-x)^2+(x+x)^2\] now solve
how did you get D ?
try again... you don't have to use a calculator it's just like (2-2)^2+ (2+2)^2

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Other answers:

16?
do you mean (2-2)^2+(2+2)^2 = 16 ??
Yeah
yeah right ...
\[\huge\rm \color{ReD}{(x-x)^2}+(x+x)^2\] now solve x-x= ?? x+x= ?? solve the parentheses
x-x=0 x+x=2x
yes right \[\huge\rm \color{ReD}{(0)^2}+(2x)^2= ??\]
2x(2x)=4x^2
So the answer is B?
yes right now replace x with cos theta = answer
Thank you!
my pleasure
Hey Vera its me starlord6200

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