(x^(5/2) + 3/(sqrt(2) )^2

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(x^(5/2) + 3/(sqrt(2) )^2

Mathematics
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And I find the first term as \[x^{5}\] and the last term as \[\frac{ 9 }{ 2 }\] but i don't understand how the middle term becomes \[3\sqrt{2}x ^{5/2}\]
\[\left( x ^{5/2}+\frac{ 3 }{ \sqrt{2} } \right)^{2}\]
\[\left( a+b \right)^2=a^2+b^2+2ab\] \[here~2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }=3\sqrt{2}x ^{\frac{ 5 }{ 2 }}\]

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Other answers:

This is the same just more of the missing steps
\[2=\left( \sqrt{2} \right)^2\]
i only solved 2ab
when I multiply 2ab I am getting \[\frac{ 6\left( \sqrt{x} \right)^{5} }{ \sqrt{2} }\] why is this not right.? @surjithayer
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here \[a=x ^{\frac{ 5 }{ 2 }}\] \[a^2=\left( x ^{\frac{ 5 }{ 2 }} \right)^2=x ^{\frac{ 5 }{ 2 }*2}=x^5\]
\[2ab=2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }\] multiply by \[\frac{ \sqrt{2} }{ \sqrt{2} }\ \[=2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }*\frac{ \sqrt{2} }{ \sqrt{2} }=2*x ^{\frac{ 5 }{ 2 } } *\frac{ 3\sqrt{2} }{ 2 } =?\]
you are also correct
oh so all you did was clear the fraction? @surjithayer
thank you
yw

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