## anonymous one year ago (x^(5/2) + 3/(sqrt(2) )^2

1. anonymous

And I find the first term as $x^{5}$ and the last term as $\frac{ 9 }{ 2 }$ but i don't understand how the middle term becomes $3\sqrt{2}x ^{5/2}$

2. anonymous

$\left( x ^{5/2}+\frac{ 3 }{ \sqrt{2} } \right)^{2}$

3. anonymous

$\left( a+b \right)^2=a^2+b^2+2ab$ $here~2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }=3\sqrt{2}x ^{\frac{ 5 }{ 2 }}$

4. triciaal

This is the same just more of the missing steps

5. anonymous

$2=\left( \sqrt{2} \right)^2$

6. anonymous

i only solved 2ab

7. anonymous

when I multiply 2ab I am getting $\frac{ 6\left( \sqrt{x} \right)^{5} }{ \sqrt{2} }$ why is this not right.? @surjithayer

8. triciaal

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9. anonymous

here $a=x ^{\frac{ 5 }{ 2 }}$ $a^2=\left( x ^{\frac{ 5 }{ 2 }} \right)^2=x ^{\frac{ 5 }{ 2 }*2}=x^5$

10. anonymous

$2ab=2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }$ multiply by $\frac{ \sqrt{2} }{ \sqrt{2} }\ \[=2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }*\frac{ \sqrt{2} }{ \sqrt{2} }=2*x ^{\frac{ 5 }{ 2 } } *\frac{ 3\sqrt{2} }{ 2 } =?$

11. anonymous

you are also correct

12. anonymous

oh so all you did was clear the fraction? @surjithayer

13. anonymous

thank you

14. anonymous

yw