anonymous
  • anonymous
(x^(5/2) + 3/(sqrt(2) )^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
And I find the first term as \[x^{5}\] and the last term as \[\frac{ 9 }{ 2 }\] but i don't understand how the middle term becomes \[3\sqrt{2}x ^{5/2}\]
anonymous
  • anonymous
\[\left( x ^{5/2}+\frac{ 3 }{ \sqrt{2} } \right)^{2}\]
anonymous
  • anonymous
\[\left( a+b \right)^2=a^2+b^2+2ab\] \[here~2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }=3\sqrt{2}x ^{\frac{ 5 }{ 2 }}\]

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triciaal
  • triciaal
This is the same just more of the missing steps
anonymous
  • anonymous
\[2=\left( \sqrt{2} \right)^2\]
anonymous
  • anonymous
i only solved 2ab
anonymous
  • anonymous
when I multiply 2ab I am getting \[\frac{ 6\left( \sqrt{x} \right)^{5} }{ \sqrt{2} }\] why is this not right.? @surjithayer
triciaal
  • triciaal
|dw:1439326019356:dw||dw:1439326112145:dw|
anonymous
  • anonymous
here \[a=x ^{\frac{ 5 }{ 2 }}\] \[a^2=\left( x ^{\frac{ 5 }{ 2 }} \right)^2=x ^{\frac{ 5 }{ 2 }*2}=x^5\]
anonymous
  • anonymous
\[2ab=2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }\] multiply by \[\frac{ \sqrt{2} }{ \sqrt{2} }\ \[=2*x ^{\frac{ 5 }{ 2 }}*\frac{ 3 }{ \sqrt{2} }*\frac{ \sqrt{2} }{ \sqrt{2} }=2*x ^{\frac{ 5 }{ 2 } } *\frac{ 3\sqrt{2} }{ 2 } =?\]
anonymous
  • anonymous
you are also correct
anonymous
  • anonymous
oh so all you did was clear the fraction? @surjithayer
anonymous
  • anonymous
thank you
anonymous
  • anonymous
yw

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