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anonymous

  • one year ago

help!

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  1. anonymous
    • one year ago
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    @mathmath333

  2. anonymous
    • one year ago
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  3. IrishBoy123
    • one year ago
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    think about \(1 - \frac {\pi r^2}{4r^2}\)

  4. IrishBoy123
    • one year ago
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    ie what it means

  5. anonymous
    • one year ago
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    is it A?

  6. IrishBoy123
    • one year ago
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    this might be be more helpful \(1−\frac {πr^2}{(2r)^2} \)

  7. IrishBoy123
    • one year ago
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    in your question, what is \(\pi r^2\) ?!

  8. IrishBoy123
    • one year ago
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    and what is \((2r)^2\) ?!

  9. Astrophysics
    • one year ago
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    I just explained this to you geny :\

  10. anonymous
    • one year ago
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    but im confused

  11. anonymous
    • one year ago
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    i dont get any of this (2r)2

  12. anonymous
    • one year ago
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    can you just give it to me in a more simple way to find the formula please

  13. IrishBoy123
    • one year ago
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    |dw:1439326130671:dw|

  14. IrishBoy123
    • one year ago
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    |dw:1439326209798:dw|

  15. IrishBoy123
    • one year ago
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    |dw:1439326313116:dw|

  16. Astrophysics
    • one year ago
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    Nice one @IrishBoy123 the drawings should help you @geny55

  17. IrishBoy123
    • one year ago
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    cheers astro! i want to become the Banksy of OS :-)

  18. Astrophysics
    • one year ago
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    Bahaha!

  19. IrishBoy123
    • one year ago
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    @geny55 you still there, mate? if this is not helping, truly just say so. i want to help, not hinder.

  20. anonymous
    • one year ago
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    its not :(

  21. Astrophysics
    • one year ago
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    Mhm ok well I think the problem you're having is understanding where the area comes from...so let me put it as simple as I can. So here is a square |dw:1439326678199:dw| the area is "inside" the square. So far so good?

  22. IrishBoy123
    • one year ago
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    @geny55 thank you for your honesty !

  23. Astrophysics
    • one year ago
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    |dw:1439326963001:dw| so since the length of all the sides are the same for the square we let the side = a, and to find the total area, we then take the length and multiply it by the width \[A_{\square} = lw = a \times a = a^2\]

  24. Astrophysics
    • one year ago
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    Maybe you should try deriving the area of circle yourself for fun :P

  25. anonymous
    • one year ago
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    im sorry i cant do this question :( i give up

  26. IrishBoy123
    • one year ago
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    oh @geny55 :(( not so. penguins are remarkable creatures. we've all seen the movies. do you know: what is the area of a circle of radius r ?!

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