anonymous
  • anonymous
help!
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
anonymous
  • anonymous
1 Attachment
IrishBoy123
  • IrishBoy123
think about \(1 - \frac {\pi r^2}{4r^2}\)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

IrishBoy123
  • IrishBoy123
ie what it means
anonymous
  • anonymous
is it A?
IrishBoy123
  • IrishBoy123
this might be be more helpful \(1−\frac {πr^2}{(2r)^2} \)
IrishBoy123
  • IrishBoy123
in your question, what is \(\pi r^2\) ?!
IrishBoy123
  • IrishBoy123
and what is \((2r)^2\) ?!
Astrophysics
  • Astrophysics
I just explained this to you geny :\
anonymous
  • anonymous
but im confused
anonymous
  • anonymous
i dont get any of this (2r)2
anonymous
  • anonymous
can you just give it to me in a more simple way to find the formula please
IrishBoy123
  • IrishBoy123
|dw:1439326130671:dw|
IrishBoy123
  • IrishBoy123
|dw:1439326209798:dw|
IrishBoy123
  • IrishBoy123
|dw:1439326313116:dw|
Astrophysics
  • Astrophysics
Nice one @IrishBoy123 the drawings should help you @geny55
IrishBoy123
  • IrishBoy123
cheers astro! i want to become the Banksy of OS :-)
Astrophysics
  • Astrophysics
Bahaha!
IrishBoy123
  • IrishBoy123
@geny55 you still there, mate? if this is not helping, truly just say so. i want to help, not hinder.
anonymous
  • anonymous
its not :(
Astrophysics
  • Astrophysics
Mhm ok well I think the problem you're having is understanding where the area comes from...so let me put it as simple as I can. So here is a square |dw:1439326678199:dw| the area is "inside" the square. So far so good?
IrishBoy123
  • IrishBoy123
@geny55 thank you for your honesty !
Astrophysics
  • Astrophysics
|dw:1439326963001:dw| so since the length of all the sides are the same for the square we let the side = a, and to find the total area, we then take the length and multiply it by the width \[A_{\square} = lw = a \times a = a^2\]
Astrophysics
  • Astrophysics
Maybe you should try deriving the area of circle yourself for fun :P
anonymous
  • anonymous
im sorry i cant do this question :( i give up
IrishBoy123
  • IrishBoy123
oh @geny55 :(( not so. penguins are remarkable creatures. we've all seen the movies. do you know: what is the area of a circle of radius r ?!

Looking for something else?

Not the answer you are looking for? Search for more explanations.