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anonymous

  • one year ago

Medal And Fan for helping me understand how to solve it Two quadratic functions are shown. Function 1: f(x) = 4x2 + 8x + 1 Function 2: x g(x) −2 2 −1 0 0 2 1 8 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (−1, −3). Function 1 has the least minimum value and its coordinates are (0, 1). Function 2 has the least minimum value and its coordinates are (−1, 0). Function 2 has the least minimum value and its coordinates are (0, 2).

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  1. anonymous
    • one year ago
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    Least minimum value is where its y value is least

  2. anonymous
    • one year ago
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    in (x,y)

  3. anonymous
    • one year ago
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    I don't understand

  4. anonymous
    • one year ago
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    would it be c because the minimum value of function 2 is lowest at point (-1,0)???

  5. triciaal
    • one year ago
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    one approach find the value of x when f(x) = 0 when g(x) = 0 x = -1 f(-1) = 4(-1)^2 + 8(-1) + 1 = when dy/dx = 0 it gives the max or min use this value in f(x) to give the value

  6. anonymous
    • one year ago
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    triciaal I do not think this is a calculus problem.

  7. anonymous
    • one year ago
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    It is more like Algebra 2

  8. anonymous
    • one year ago
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    which value of y is the least in the multiple choice? y is inside (x,y)

  9. triciaal
    • one year ago
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    |dw:1439326914459:dw|

  10. anonymous
    • one year ago
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    I think I understand. It's A because its suppose to be the point (-1,-3) is the least in value

  11. anonymous
    • one year ago
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    If you solve the problem through quadratic formula you get what @triciaal got

  12. anonymous
    • one year ago
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    yes, but since it is a multiply choice you can just figure which one has the least value of all the choices.

  13. anonymous
    • one year ago
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    I just wanted to make sure it wasn't a trick question because...

  14. anonymous
    • one year ago
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    last time i did something it was wrong because i used that logic

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