Medal And Fan for helping me understand how to solve it Two quadratic functions are shown. Function 1: f(x) = 4x2 + 8x + 1 Function 2: x g(x) −2 2 −1 0 0 2 1 8 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (−1, −3). Function 1 has the least minimum value and its coordinates are (0, 1). Function 2 has the least minimum value and its coordinates are (−1, 0). Function 2 has the least minimum value and its coordinates are (0, 2).

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Medal And Fan for helping me understand how to solve it Two quadratic functions are shown. Function 1: f(x) = 4x2 + 8x + 1 Function 2: x g(x) −2 2 −1 0 0 2 1 8 Which function has the least minimum value and what are its coordinates? Function 1 has the least minimum value and its coordinates are (−1, −3). Function 1 has the least minimum value and its coordinates are (0, 1). Function 2 has the least minimum value and its coordinates are (−1, 0). Function 2 has the least minimum value and its coordinates are (0, 2).

Mathematics
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Least minimum value is where its y value is least
in (x,y)
I don't understand

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would it be c because the minimum value of function 2 is lowest at point (-1,0)???
one approach find the value of x when f(x) = 0 when g(x) = 0 x = -1 f(-1) = 4(-1)^2 + 8(-1) + 1 = when dy/dx = 0 it gives the max or min use this value in f(x) to give the value
triciaal I do not think this is a calculus problem.
It is more like Algebra 2
which value of y is the least in the multiple choice? y is inside (x,y)
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I think I understand. It's A because its suppose to be the point (-1,-3) is the least in value
If you solve the problem through quadratic formula you get what @triciaal got
yes, but since it is a multiply choice you can just figure which one has the least value of all the choices.
I just wanted to make sure it wasn't a trick question because...
last time i did something it was wrong because i used that logic

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