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anonymous
 one year ago
find the volume 2.5ft and 10 ft the options are
24.5ft
20.5 ft
48 ft
49 ft
anonymous
 one year ago
find the volume 2.5ft and 10 ft the options are 24.5ft 20.5 ft 48 ft 49 ft

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0exactly @Astrophysics what are we finding the volume of

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the formula is v=pie r2 h

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Can you post the full problem

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Or take an image of it and post it here

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0I noticed it's a cylinder

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes please put the whole problem that will help us hep u

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0What does 2.5 ft and 10 ft mean, is 2.5 ft the radius, is 10 ft the height?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think 2.5 is the radius and 10 is the height

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on i am trying to send it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0If so just use the formula they provided then \[V = \pi r^2 h \implies \pi (2.5)^2(10)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you get 196.35 though?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Yeah lets just wait for the problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I still got 196.35 what did u get @Astrophysics

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439328678620:dw so this is your problem either you're missing information or it's 62 pi ft^3

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0All your answers are in ft? Then that's not the volume

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually cubic feet sorry

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Are you sure that's the information..?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Then that's it \[V= \pi r^2 h = \pi (2.5)^2 (10) = 62.5 \pi~ ft^3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry I couldn't help :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much for trying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just figured it out its 49

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0What did it say :o

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah I am wondering that to

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well i had to first do d=2r and then v=3.14(1.25)(10) came out to be 49

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0What? That makes no sense

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0we were using radius in the formula not diameter it shouldn't matter

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know but that what my teacher told me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that doesn't make sense I just solved it and got something total different than 49

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0The formula is V = pi r^2 h...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i thought it was rather confusing

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Your teacher is wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not to be rude but I agree with both of u

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0I mean you can use diamater, but there is not need

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not being rude but sometimes teachers need to pay attention to their own way of stating a problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just thought that i should let you all know what the answer was
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