## anonymous one year ago Find the slope of the cardioid r=2+2cos(theta) at the point corresponding to (theta)=pi/4

1. IrishBoy123

$$r=2+2cos(\theta)$$ the slope takes you back into cartesian, ok? so you want $$\frac{dy}{dx}$$ yep?

2. anonymous

This one specifically is nothing like the ones I've done in my previous assignment. So I'm confused as to how to even begin to tackle it.

3. anonymous

wouldn't the tangent of pi/4 in this case be the slope?

4. IrishBoy123

totally

5. IrishBoy123

do you know how to do that?

6. IrishBoy123
7. anonymous

totally makes sense now that I have the graph! thanks!

8. IrishBoy123

cool!

9. anonymous

I have one more question. Maybe you can help with this one too, because MacLaurin Series are my weakest topic in this course so far.

10. IrishBoy123

just to complete this thread, the formula to get the slope in cartesian is $$\large \frac{dy}{dx} = \frac{\frac {d r}{d \theta} \ sin \theta + r \ cos \theta}{\frac {d r}{d \theta} \ cos \theta - r sin \theta}$$ very deriveable....from the basic premises that $$x = r cos \theta$$ etc

11. IrishBoy123

maclaurin no worries stick it in a new thread first, though