anonymous
  • anonymous
Find the slope of the cardioid r=2+2cos(theta) at the point corresponding to (theta)=pi/4
Mathematics
katieb
  • katieb
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IrishBoy123
  • IrishBoy123
\(r=2+2cos(\theta)\) the slope takes you back into cartesian, ok? so you want \(\frac{dy}{dx}\) yep?
anonymous
  • anonymous
This one specifically is nothing like the ones I've done in my previous assignment. So I'm confused as to how to even begin to tackle it.
anonymous
  • anonymous
wouldn't the tangent of pi/4 in this case be the slope?

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IrishBoy123
  • IrishBoy123
totally
IrishBoy123
  • IrishBoy123
do you know how to do that?
IrishBoy123
  • IrishBoy123
this is it https://www.desmos.com/calculator/qysgdfnvnr
anonymous
  • anonymous
totally makes sense now that I have the graph! thanks!
IrishBoy123
  • IrishBoy123
cool!
anonymous
  • anonymous
I have one more question. Maybe you can help with this one too, because MacLaurin Series are my weakest topic in this course so far.
IrishBoy123
  • IrishBoy123
just to complete this thread, the formula to get the slope in cartesian is \(\large \frac{dy}{dx} = \frac{\frac {d r}{d \theta} \ sin \theta + r \ cos \theta}{\frac {d r}{d \theta} \ cos \theta - r sin \theta}\) very deriveable....from the basic premises that \(x = r cos \theta \) etc
IrishBoy123
  • IrishBoy123
maclaurin no worries stick it in a new thread first, though

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