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anonymous

  • one year ago

Find the slope of the cardioid r=2+2cos(theta) at the point corresponding to (theta)=pi/4

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  1. IrishBoy123
    • one year ago
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    \(r=2+2cos(\theta)\) the slope takes you back into cartesian, ok? so you want \(\frac{dy}{dx}\) yep?

  2. anonymous
    • one year ago
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    This one specifically is nothing like the ones I've done in my previous assignment. So I'm confused as to how to even begin to tackle it.

  3. anonymous
    • one year ago
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    wouldn't the tangent of pi/4 in this case be the slope?

  4. IrishBoy123
    • one year ago
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    totally

  5. IrishBoy123
    • one year ago
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    do you know how to do that?

  6. IrishBoy123
    • one year ago
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    this is it https://www.desmos.com/calculator/qysgdfnvnr

  7. anonymous
    • one year ago
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    totally makes sense now that I have the graph! thanks!

  8. IrishBoy123
    • one year ago
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    cool!

  9. anonymous
    • one year ago
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    I have one more question. Maybe you can help with this one too, because MacLaurin Series are my weakest topic in this course so far.

  10. IrishBoy123
    • one year ago
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    just to complete this thread, the formula to get the slope in cartesian is \(\large \frac{dy}{dx} = \frac{\frac {d r}{d \theta} \ sin \theta + r \ cos \theta}{\frac {d r}{d \theta} \ cos \theta - r sin \theta}\) very deriveable....from the basic premises that \(x = r cos \theta \) etc

  11. IrishBoy123
    • one year ago
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    maclaurin no worries stick it in a new thread first, though

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