anonymous
  • anonymous
Fan and Medal Im confused please help Solve: 5x2 + 25x = 0.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
How would I get this into quadratic formula without a c variable
anonymous
  • anonymous
@jim_thompson5910 @Vocaloid @Hero
anonymous
  • anonymous
Then you do not use c at all The 4ac becomes 0 in the equation.

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anonymous
  • anonymous
out of my answer choices what would it be then? I'm confused at how you would plug it in and still get the answer
anonymous
  • anonymous
x = 0, x = 5 x = 0, x = −5 x = −5, x = 0, x = 5 x = 5, x = 25
anonymous
  • anonymous
-b\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
anonymous
  • anonymous
ax^2+bx+c so a=5 and b=25
anonymous
  • anonymous
so it would be -25 =+/- sqrt of 25 all over 10
anonymous
  • anonymous
i got it thanks
anonymous
  • anonymous
\[\frac{ -25\pm \sqrt{25^2-4(5)(0)} }{ 2(5) }\] \[\frac{ -25\pm \sqrt{625} }{ 10 }\] \[\frac{ -25\pm25 }{ 10 }\] using addition it is \[\frac{ -25+25 }{ 10 }=0\] using subtraction it is \[\frac{ -25-25 }{ 10}=-5\]
anonymous
  • anonymous
Glad you did :)
anonymous
  • anonymous
wait it is not square root of 25. You mean square root of 625 since it is b^2 not b
Jack1
  • Jack1
all good now?

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