Y=1+srwt(x), y=1+.5x. Find the area of region

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Y=1+srwt(x), y=1+.5x. Find the area of region

Mathematics
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First equation is =1+sqrt(x)
\(y=1+\sqrt{x}\) \(y=1+\frac{1}{2}x\)
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So what is the area?

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Other answers:

Steps: 1. Find where both curves intercept using systems of equation 2. Figure out which function is larger by simply inputing a number inbetween the two intercept bounds 3. Integrate in respect to x using intercepts as bounds for the intgrals Set up an integral for the larger function Set up an integral for the smaller function 5. Subtract the larger function integral from the smaller function integral If you get a negative you subtracted them incorrectly ( you confused the smaller function for the larger function)
So can you find your intercepts?
No and I'm late for dinner can u just share the area?
so the area is \(\large \int_{0}^{4} (1 + \sqrt{x}) - (1+\frac{1}{2}x) \ dx\) \(\large = [ \ (x + \frac{2}{3}x^{3/2} - x - \frac{1}{4}x^2) \ ]_{0}^{4}\) \(\large = [ \ ( \frac{2}{3}x^{3/2} - \frac{1}{4}x^2) \ ]_{0}^{4}\) \(\large = \frac{2}{3}(4)^{3/2} - \frac{1}{4}(4)^2 = \frac{4}{3}\)
did you get that also?
Yes
cool! good night!

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