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anonymous
 one year ago
Y=1+srwt(x), y=1+.5x. Find the area of region
anonymous
 one year ago
Y=1+srwt(x), y=1+.5x. Find the area of region

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First equation is =1+sqrt(x)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\(y=1+\sqrt{x}\) \(y=1+\frac{1}{2}x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what is the area?

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.1Steps: 1. Find where both curves intercept using systems of equation 2. Figure out which function is larger by simply inputing a number inbetween the two intercept bounds 3. Integrate in respect to x using intercepts as bounds for the intgrals Set up an integral for the larger function Set up an integral for the smaller function 5. Subtract the larger function integral from the smaller function integral If you get a negative you subtracted them incorrectly ( you confused the smaller function for the larger function)

Australopithecus
 one year ago
Best ResponseYou've already chosen the best response.1So can you find your intercepts?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No and I'm late for dinner can u just share the area?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1so the area is \(\large \int_{0}^{4} (1 + \sqrt{x})  (1+\frac{1}{2}x) \ dx\) \(\large = [ \ (x + \frac{2}{3}x^{3/2}  x  \frac{1}{4}x^2) \ ]_{0}^{4}\) \(\large = [ \ ( \frac{2}{3}x^{3/2}  \frac{1}{4}x^2) \ ]_{0}^{4}\) \(\large = \frac{2}{3}(4)^{3/2}  \frac{1}{4}(4)^2 = \frac{4}{3}\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1did you get that also?
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