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anonymous

  • one year ago

nick1234567 Area of one leaf of the rose r=3sin(4theta)

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  1. Michele_Laino
    • one year ago
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    I'm very sorry, it is 2:38 a.m. (Italy time zone) from me so I have to go to sleep

  2. anonymous
    • one year ago
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    Please help!

  3. anonymous
    • one year ago
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    Need answer in next 3 mins please

  4. anonymous
    • one year ago
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    Ur the best!

  5. pooja195
    • one year ago
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    ok any ideas on where to start?

  6. anonymous
    • one year ago
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    Nope no clue and it's my last prob due in 3 mins

  7. anonymous
    • one year ago
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    Can u please save me

  8. pooja195
    • one year ago
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    http://www.wolframalpha.com/input/?i=r%3D3sin%284theta%29

  9. anonymous
    • one year ago
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    So? Area is?

  10. anonymous
    • one year ago
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    Only have 1min left thank u again

  11. anonymous
    • one year ago
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    Ideas???

  12. anonymous
    • one year ago
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    Needs suggestion in the ext 39 sec

  13. pooja195
    • one year ago
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    Things like this cant be done in that much time. You need to make sure you have time for it

  14. pooja195
    • one year ago
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    You will need to use \[\huge~\rm~\int\limits_{}^{}1/2r^2d \emptyset\]

  15. IrishBoy123
    • one year ago
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    if this is an emergency, this is a brief attempt: \(r=3sin(4 \theta)\) \(r = 0, \ 4\theta = 0, \ \pi \implies \theta = 0, \pi/4, ....\) \(A = \frac{1}{2} \int_{0}^{\pi / 4} 9 sin^2 (4 \theta) \ d \theta \) \( = \frac{9}{4} \ \int_{0}^{\pi / 4} 1 - cos \ 8 \theta \ d \theta\) \( = \frac{9}{4} \ [ \theta - \frac{1}{8}sin \ 8 \theta \ ]_{0}^{\pi / 4}\) \( = \frac{9}{4} \ [ \frac{\pi}{4} ] = \frac{9 \pi}{16}\)

  16. pooja195
    • one year ago
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    ^or that works too ;p

  17. pooja195
    • one year ago
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    You will need to use \[\huge~\rm~\int\limits_{}^{}1/2r^2d \theta\] \[\huge~\rm~\int\limits\limits_{\alpha }^{\beta }1/2r^2d \theta \] \[\huge~\rm~\int\limits\limits\limits_{0 }^{\ \pi/4 }1/2(3\sin(4\theta))^2d \theta =\frac{ 9 }{ 16 }\pi \]

  18. Jack1
    • one year ago
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    lol... why is this q orange?

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