nick1234567 Area of one leaf of the rose r=3sin(4theta)

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nick1234567 Area of one leaf of the rose r=3sin(4theta)

Mathematics
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I'm very sorry, it is 2:38 a.m. (Italy time zone) from me so I have to go to sleep
Please help!
Need answer in next 3 mins please

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Ur the best!
ok any ideas on where to start?
Nope no clue and it's my last prob due in 3 mins
Can u please save me
http://www.wolframalpha.com/input/?i=r%3D3sin%284theta%29
So? Area is?
Only have 1min left thank u again
Ideas???
Needs suggestion in the ext 39 sec
Things like this cant be done in that much time. You need to make sure you have time for it
You will need to use \[\huge~\rm~\int\limits_{}^{}1/2r^2d \emptyset\]
if this is an emergency, this is a brief attempt: \(r=3sin(4 \theta)\) \(r = 0, \ 4\theta = 0, \ \pi \implies \theta = 0, \pi/4, ....\) \(A = \frac{1}{2} \int_{0}^{\pi / 4} 9 sin^2 (4 \theta) \ d \theta \) \( = \frac{9}{4} \ \int_{0}^{\pi / 4} 1 - cos \ 8 \theta \ d \theta\) \( = \frac{9}{4} \ [ \theta - \frac{1}{8}sin \ 8 \theta \ ]_{0}^{\pi / 4}\) \( = \frac{9}{4} \ [ \frac{\pi}{4} ] = \frac{9 \pi}{16}\)
^or that works too ;p
You will need to use \[\huge~\rm~\int\limits_{}^{}1/2r^2d \theta\] \[\huge~\rm~\int\limits\limits_{\alpha }^{\beta }1/2r^2d \theta \] \[\huge~\rm~\int\limits\limits\limits_{0 }^{\ \pi/4 }1/2(3\sin(4\theta))^2d \theta =\frac{ 9 }{ 16 }\pi \]
lol... why is this q orange?

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