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anonymous

  • one year ago

Help with combustion?

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  1. anonymous
    • one year ago
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    Has anyone done the combustion assignment for chemistry on flvs?

  2. anonymous
    • one year ago
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    For example I have to find out the reaction type of Fe2O3 + CuSO4, and I said combustion/synthesis.

  3. Astrophysics
    • one year ago
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    A combustion is as follow \[C_xH_y + O_2 -> CO_2+H_2O\]

  4. Astrophysics
    • one year ago
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    Your reaction type would be a double replacement

  5. Astrophysics
    • one year ago
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    Here I'll make you a simple summary of the reactions

  6. anonymous
    • one year ago
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    CO2 + H2O is only if it's a hydrocarbon combusting, no?

  7. Astrophysics
    • one year ago
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    \[AB -> A+B ~~~(decomposition)\] \[A+B -> AB ~~~~(composition/ synthesis)\] \[AB+C -> AC+B ~~~ \text{(singe replacement, depends upon metal and nonmetal)}\] \[AB+CD -> AD+CB ~~~~(double~replacement)\] and you have the combustion reaction above

  8. anonymous
    • one year ago
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    Oh alright. So I'd be right in saying that Pb(NO3)2+ KI is combustion/single replacement?

  9. Astrophysics
    • one year ago
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    Note, for double replacement, A and C are metals B and D are non metals

  10. Astrophysics
    • one year ago
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    Those are not combustions

  11. Astrophysics
    • one year ago
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    A single replacement sounds good though

  12. anonymous
    • one year ago
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    How do I tell if it's a combustion or not if oxygen is present?

  13. Astrophysics
    • one year ago
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    Well I haven't taken too much chemistry but a combustion is in the form of \[C_xH_y + O_2 -> CO_2+H_2O\]

  14. anonymous
    • one year ago
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    That's only hydrocarbon combustions. inorganic molecules combust as well.

  15. Astrophysics
    • one year ago
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    This is the general form of a combustion reaction, what you're thinking of is, that in general anything with oxygen can be considered combustion.

  16. Astrophysics
    • one year ago
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    That's why there is a general form of the equation to avoid confusion

  17. anonymous
    • one year ago
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    So the general form of combustion only includes carbon+hydrogen and oxygen?

  18. Astrophysics
    • one year ago
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    Yes, generally we say combustion is the reaction of oxygen with an compound of carbon and hydrogen

  19. anonymous
    • one year ago
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    What about inorganic combustions?

  20. Astrophysics
    • one year ago
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    Well let me tag someone else who's better at chemistry that may be able to explain this @empty

  21. anonymous
    • one year ago
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    Alright. Thank you for your help! I appreciate it.

  22. Astrophysics
    • one year ago
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    Np @nincompoop maybe able to help you as well

  23. anonymous
    • one year ago
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    What do you think nincompoop?

  24. nincompoop
    • one year ago
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    Fe2O3 + CuSO4 do you want to figure what kind of reaction will take place?

  25. anonymous
    • one year ago
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    Yes. Also, what determines if it will be a combustion if not just having oxygen present?

  26. anonymous
    • one year ago
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    So the undermentioned reaction is combustion?

  27. anonymous
    • one year ago
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    Is there a rule of exception?

  28. anonymous
    • one year ago
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    *aforementioned

  29. nincompoop
    • one year ago
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    correct

  30. anonymous
    • one year ago
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    As well as double replacement?

  31. Astrophysics
    • one year ago
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    Definitely a double replacement

  32. nincompoop
    • one year ago
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    Fe2O3 + CuSO4 ye double replacement

  33. anonymous
    • one year ago
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    Ok, one more for practice.

  34. nincompoop
    • one year ago
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    http://chemwiki.ucdavis.edu/Analytical_Chemistry/Chemical_Reactions/Chemical_Reactions

  35. anonymous
    • one year ago
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    Mg+Hcl would be single replacement, but not combustion because there's no oxygen?

  36. nincompoop
    • one year ago
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    correct

  37. anonymous
    • one year ago
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    HCl*

  38. nincompoop
    • one year ago
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    but you have to take note that Oxygen is abundant in the atmosphere and it is difficult to do these experiments in an environment where there is no oxygen the rule of thumb is that whenever there is an addition of oxygen, that is a combustion reaction

  39. nincompoop
    • one year ago
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    but in the cases of your problem, it is more important to know single replacement, double replacement, redox reaction (a type of combustion and can have no oxygen in the equation), decomposition and synthesis. later on in your chemistry experiences, these names do not matter much because you will be focusing on movement of electrons for the most case.

  40. nincompoop
    • one year ago
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    use the formula that astro provided you and usually you can pretty much tell or make a good guess with the number of substances present in the reaction

  41. Astrophysics
    • one year ago
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    \[Fe_2O_3+3CuSO_4 ->Fe_2(SO_2)_3+3CuO\]

  42. nincompoop
    • one year ago
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    there is nothing more to it, and you will be focusing more on balancing equations and calculating enthalpy, spontaneity, gibbs free and other exciting things about chemistry

  43. Astrophysics
    • one year ago
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    Mhm

  44. Astrophysics
    • one year ago
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    Is that still considered a combustion

  45. nincompoop
    • one year ago
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    the SO will be treated as on compound \(\sf (SO_4) \)

  46. Astrophysics
    • one year ago
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    oh oops that should be SO_4 but yeah

  47. anonymous
    • one year ago
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    Noted 'poop. Does SO_4 being treated that way change whether it's a combustion or not?

  48. nincompoop
    • one year ago
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    which should have been covered in other lessons like lewis structures, ground charge and formal charges.

  49. nincompoop
    • one year ago
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    nah it is minute and shouldn't be the focus of concern

  50. nincompoop
    • one year ago
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    oxygen makes everything combustible and very reactive, let us just put it that way

  51. anonymous
    • one year ago
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    OK. I think I got it. You've all been tremendous help. I really appreciate it. Just curious though, what do you guys do for a job (school maybe)?

  52. anonymous
    • one year ago
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    Professional amphibian lawyer/politician.

  53. anonymous
    • one year ago
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    Well see you later 'gater.

  54. nincompoop
    • one year ago
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    woodward gives a good way to capture these concepts do not shy away from asking him LAUGHING OUT LOUD

  55. anonymous
    • one year ago
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    OK. Is there anything that you think I don't understand or that wasn't covered thoroughly enough you feel, woodward?

  56. anonymous
    • one year ago
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    Actually this is unbalanced: \[C_xH_y + O_2 -> CO_2+H_2O\] Nope, nothing really to add really, only because chemistry has too much to say about everything lol

  57. nincompoop
    • one year ago
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    :) I was hoping someone will see that

  58. nincompoop
    • one year ago
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    hahaha

  59. Astrophysics
    • one year ago
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    It's just a template/equation reason why it's CxHy

  60. anonymous
    • one year ago
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    medal + fan if you can balance it before me. :)

  61. anonymous
    • one year ago
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    Oh, beat me to it! How do I reward everyone for the help?

  62. nincompoop
    • one year ago
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    do it

  63. anonymous
    • one year ago
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    The balance? Well, assuming C_1H_1, then...

  64. Astrophysics
    • one year ago
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    You click "best response" which gives the user a medal, unfortunately you can only pick 1.

  65. Astrophysics
    • one year ago
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    Try CH4 methane

  66. anonymous
    • one year ago
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    Alright

  67. anonymous
    • one year ago
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    I think this is it: \[4C_xH_y + O_2 \rightarrow 4x CO_2+2yH_2O\]

  68. anonymous
    • one year ago
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    CxHy+O2−>CO2+H2O CH4+4O2 -> CO2 +2H2O I guess

  69. anonymous
    • one year ago
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    Wait

  70. anonymous
    • one year ago
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    2O2*

  71. Astrophysics
    • one year ago
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    When you're balancing a combustion like that, do it in this order, CHO

  72. anonymous
    • one year ago
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    Yeah my answer is clearly wrong, there's no coefficient on \(O_2\)!

  73. anonymous
    • one year ago
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    Well thanks guys! I've chosen Astro as best response because of consistent attendance and great help.

  74. Astrophysics
    • one year ago
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    Let me correct your eqatuon Professor

  75. Astrophysics
    • one year ago
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    For CH4 and we can conclude then :-)

  76. Astrophysics
    • one year ago
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    \[CH_4 + 2O_2 -> CO_2+2H_2O\]

  77. anonymous
    • one year ago
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    I corrected it to that I think :)

  78. Astrophysics
    • one year ago
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    Ok great!

  79. Astrophysics
    • one year ago
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    Sorry I didn't see that post haha, well done!

  80. anonymous
    • one year ago
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    Alright I'll be off then! Thanks guys!

  81. Astrophysics
    • one year ago
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    Np, take care!

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