anonymous
  • anonymous
Help with combustion?
Chemistry
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Has anyone done the combustion assignment for chemistry on flvs?
anonymous
  • anonymous
For example I have to find out the reaction type of Fe2O3 + CuSO4, and I said combustion/synthesis.
Astrophysics
  • Astrophysics
A combustion is as follow \[C_xH_y + O_2 -> CO_2+H_2O\]

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Astrophysics
  • Astrophysics
Your reaction type would be a double replacement
Astrophysics
  • Astrophysics
Here I'll make you a simple summary of the reactions
anonymous
  • anonymous
CO2 + H2O is only if it's a hydrocarbon combusting, no?
Astrophysics
  • Astrophysics
\[AB -> A+B ~~~(decomposition)\] \[A+B -> AB ~~~~(composition/ synthesis)\] \[AB+C -> AC+B ~~~ \text{(singe replacement, depends upon metal and nonmetal)}\] \[AB+CD -> AD+CB ~~~~(double~replacement)\] and you have the combustion reaction above
anonymous
  • anonymous
Oh alright. So I'd be right in saying that Pb(NO3)2+ KI is combustion/single replacement?
Astrophysics
  • Astrophysics
Note, for double replacement, A and C are metals B and D are non metals
Astrophysics
  • Astrophysics
Those are not combustions
Astrophysics
  • Astrophysics
A single replacement sounds good though
anonymous
  • anonymous
How do I tell if it's a combustion or not if oxygen is present?
Astrophysics
  • Astrophysics
Well I haven't taken too much chemistry but a combustion is in the form of \[C_xH_y + O_2 -> CO_2+H_2O\]
anonymous
  • anonymous
That's only hydrocarbon combustions. inorganic molecules combust as well.
Astrophysics
  • Astrophysics
This is the general form of a combustion reaction, what you're thinking of is, that in general anything with oxygen can be considered combustion.
Astrophysics
  • Astrophysics
That's why there is a general form of the equation to avoid confusion
anonymous
  • anonymous
So the general form of combustion only includes carbon+hydrogen and oxygen?
Astrophysics
  • Astrophysics
Yes, generally we say combustion is the reaction of oxygen with an compound of carbon and hydrogen
anonymous
  • anonymous
What about inorganic combustions?
Astrophysics
  • Astrophysics
Well let me tag someone else who's better at chemistry that may be able to explain this @empty
anonymous
  • anonymous
Alright. Thank you for your help! I appreciate it.
Astrophysics
  • Astrophysics
Np @nincompoop maybe able to help you as well
anonymous
  • anonymous
What do you think nincompoop?
nincompoop
  • nincompoop
Fe2O3 + CuSO4 do you want to figure what kind of reaction will take place?
anonymous
  • anonymous
Yes. Also, what determines if it will be a combustion if not just having oxygen present?
anonymous
  • anonymous
So the undermentioned reaction is combustion?
anonymous
  • anonymous
Is there a rule of exception?
anonymous
  • anonymous
*aforementioned
nincompoop
  • nincompoop
correct
anonymous
  • anonymous
As well as double replacement?
Astrophysics
  • Astrophysics
Definitely a double replacement
nincompoop
  • nincompoop
Fe2O3 + CuSO4 ye double replacement
anonymous
  • anonymous
Ok, one more for practice.
nincompoop
  • nincompoop
http://chemwiki.ucdavis.edu/Analytical_Chemistry/Chemical_Reactions/Chemical_Reactions
anonymous
  • anonymous
Mg+Hcl would be single replacement, but not combustion because there's no oxygen?
nincompoop
  • nincompoop
correct
anonymous
  • anonymous
HCl*
nincompoop
  • nincompoop
but you have to take note that Oxygen is abundant in the atmosphere and it is difficult to do these experiments in an environment where there is no oxygen the rule of thumb is that whenever there is an addition of oxygen, that is a combustion reaction
nincompoop
  • nincompoop
but in the cases of your problem, it is more important to know single replacement, double replacement, redox reaction (a type of combustion and can have no oxygen in the equation), decomposition and synthesis. later on in your chemistry experiences, these names do not matter much because you will be focusing on movement of electrons for the most case.
nincompoop
  • nincompoop
use the formula that astro provided you and usually you can pretty much tell or make a good guess with the number of substances present in the reaction
Astrophysics
  • Astrophysics
\[Fe_2O_3+3CuSO_4 ->Fe_2(SO_2)_3+3CuO\]
nincompoop
  • nincompoop
there is nothing more to it, and you will be focusing more on balancing equations and calculating enthalpy, spontaneity, gibbs free and other exciting things about chemistry
Astrophysics
  • Astrophysics
Mhm
Astrophysics
  • Astrophysics
Is that still considered a combustion
nincompoop
  • nincompoop
the SO will be treated as on compound \(\sf (SO_4) \)
Astrophysics
  • Astrophysics
oh oops that should be SO_4 but yeah
anonymous
  • anonymous
Noted 'poop. Does SO_4 being treated that way change whether it's a combustion or not?
nincompoop
  • nincompoop
which should have been covered in other lessons like lewis structures, ground charge and formal charges.
nincompoop
  • nincompoop
nah it is minute and shouldn't be the focus of concern
nincompoop
  • nincompoop
oxygen makes everything combustible and very reactive, let us just put it that way
anonymous
  • anonymous
OK. I think I got it. You've all been tremendous help. I really appreciate it. Just curious though, what do you guys do for a job (school maybe)?
anonymous
  • anonymous
Professional amphibian lawyer/politician.
anonymous
  • anonymous
Well see you later 'gater.
nincompoop
  • nincompoop
woodward gives a good way to capture these concepts do not shy away from asking him LAUGHING OUT LOUD
anonymous
  • anonymous
OK. Is there anything that you think I don't understand or that wasn't covered thoroughly enough you feel, woodward?
anonymous
  • anonymous
Actually this is unbalanced: \[C_xH_y + O_2 -> CO_2+H_2O\] Nope, nothing really to add really, only because chemistry has too much to say about everything lol
nincompoop
  • nincompoop
:) I was hoping someone will see that
nincompoop
  • nincompoop
hahaha
Astrophysics
  • Astrophysics
It's just a template/equation reason why it's CxHy
anonymous
  • anonymous
medal + fan if you can balance it before me. :)
anonymous
  • anonymous
Oh, beat me to it! How do I reward everyone for the help?
nincompoop
  • nincompoop
do it
anonymous
  • anonymous
The balance? Well, assuming C_1H_1, then...
Astrophysics
  • Astrophysics
You click "best response" which gives the user a medal, unfortunately you can only pick 1.
Astrophysics
  • Astrophysics
Try CH4 methane
anonymous
  • anonymous
Alright
anonymous
  • anonymous
I think this is it: \[4C_xH_y + O_2 \rightarrow 4x CO_2+2yH_2O\]
anonymous
  • anonymous
CxHy+O2−>CO2+H2O CH4+4O2 -> CO2 +2H2O I guess
anonymous
  • anonymous
Wait
anonymous
  • anonymous
2O2*
Astrophysics
  • Astrophysics
When you're balancing a combustion like that, do it in this order, CHO
anonymous
  • anonymous
Yeah my answer is clearly wrong, there's no coefficient on \(O_2\)!
anonymous
  • anonymous
Well thanks guys! I've chosen Astro as best response because of consistent attendance and great help.
Astrophysics
  • Astrophysics
Let me correct your eqatuon Professor
Astrophysics
  • Astrophysics
For CH4 and we can conclude then :-)
Astrophysics
  • Astrophysics
\[CH_4 + 2O_2 -> CO_2+2H_2O\]
anonymous
  • anonymous
I corrected it to that I think :)
Astrophysics
  • Astrophysics
Ok great!
Astrophysics
  • Astrophysics
Sorry I didn't see that post haha, well done!
anonymous
  • anonymous
Alright I'll be off then! Thanks guys!
Astrophysics
  • Astrophysics
Np, take care!

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