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anonymous
 one year ago
Help with combustion?
anonymous
 one year ago
Help with combustion?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Has anyone done the combustion assignment for chemistry on flvs?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For example I have to find out the reaction type of Fe2O3 + CuSO4, and I said combustion/synthesis.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3A combustion is as follow \[C_xH_y + O_2 > CO_2+H_2O\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Your reaction type would be a double replacement

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Here I'll make you a simple summary of the reactions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0CO2 + H2O is only if it's a hydrocarbon combusting, no?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3\[AB > A+B ~~~(decomposition)\] \[A+B > AB ~~~~(composition/ synthesis)\] \[AB+C > AC+B ~~~ \text{(singe replacement, depends upon metal and nonmetal)}\] \[AB+CD > AD+CB ~~~~(double~replacement)\] and you have the combustion reaction above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh alright. So I'd be right in saying that Pb(NO3)2+ KI is combustion/single replacement?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Note, for double replacement, A and C are metals B and D are non metals

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Those are not combustions

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3A single replacement sounds good though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I tell if it's a combustion or not if oxygen is present?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Well I haven't taken too much chemistry but a combustion is in the form of \[C_xH_y + O_2 > CO_2+H_2O\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's only hydrocarbon combustions. inorganic molecules combust as well.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3This is the general form of a combustion reaction, what you're thinking of is, that in general anything with oxygen can be considered combustion.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3That's why there is a general form of the equation to avoid confusion

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the general form of combustion only includes carbon+hydrogen and oxygen?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Yes, generally we say combustion is the reaction of oxygen with an compound of carbon and hydrogen

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What about inorganic combustions?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Well let me tag someone else who's better at chemistry that may be able to explain this @empty

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright. Thank you for your help! I appreciate it.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Np @nincompoop maybe able to help you as well

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you think nincompoop?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1Fe2O3 + CuSO4 do you want to figure what kind of reaction will take place?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. Also, what determines if it will be a combustion if not just having oxygen present?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the undermentioned reaction is combustion?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is there a rule of exception?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As well as double replacement?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Definitely a double replacement

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1Fe2O3 + CuSO4 ye double replacement

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, one more for practice.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1http://chemwiki.ucdavis.edu/Analytical_Chemistry/Chemical_Reactions/Chemical_Reactions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mg+Hcl would be single replacement, but not combustion because there's no oxygen?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1but you have to take note that Oxygen is abundant in the atmosphere and it is difficult to do these experiments in an environment where there is no oxygen the rule of thumb is that whenever there is an addition of oxygen, that is a combustion reaction

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1but in the cases of your problem, it is more important to know single replacement, double replacement, redox reaction (a type of combustion and can have no oxygen in the equation), decomposition and synthesis. later on in your chemistry experiences, these names do not matter much because you will be focusing on movement of electrons for the most case.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1use the formula that astro provided you and usually you can pretty much tell or make a good guess with the number of substances present in the reaction

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3\[Fe_2O_3+3CuSO_4 >Fe_2(SO_2)_3+3CuO\]

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1there is nothing more to it, and you will be focusing more on balancing equations and calculating enthalpy, spontaneity, gibbs free and other exciting things about chemistry

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Is that still considered a combustion

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1the SO will be treated as on compound \(\sf (SO_4) \)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3oh oops that should be SO_4 but yeah

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Noted 'poop. Does SO_4 being treated that way change whether it's a combustion or not?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1which should have been covered in other lessons like lewis structures, ground charge and formal charges.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1nah it is minute and shouldn't be the focus of concern

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1oxygen makes everything combustible and very reactive, let us just put it that way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK. I think I got it. You've all been tremendous help. I really appreciate it. Just curious though, what do you guys do for a job (school maybe)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Professional amphibian lawyer/politician.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well see you later 'gater.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1woodward gives a good way to capture these concepts do not shy away from asking him LAUGHING OUT LOUD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK. Is there anything that you think I don't understand or that wasn't covered thoroughly enough you feel, woodward?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually this is unbalanced: \[C_xH_y + O_2 > CO_2+H_2O\] Nope, nothing really to add really, only because chemistry has too much to say about everything lol

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1:) I was hoping someone will see that

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3It's just a template/equation reason why it's CxHy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0medal + fan if you can balance it before me. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, beat me to it! How do I reward everyone for the help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The balance? Well, assuming C_1H_1, then...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3You click "best response" which gives the user a medal, unfortunately you can only pick 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think this is it: \[4C_xH_y + O_2 \rightarrow 4x CO_2+2yH_2O\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0CxHy+O2−>CO2+H2O CH4+4O2 > CO2 +2H2O I guess

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3When you're balancing a combustion like that, do it in this order, CHO

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah my answer is clearly wrong, there's no coefficient on \(O_2\)!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well thanks guys! I've chosen Astro as best response because of consistent attendance and great help.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Let me correct your eqatuon Professor

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3For CH4 and we can conclude then :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3\[CH_4 + 2O_2 > CO_2+2H_2O\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I corrected it to that I think :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.3Sorry I didn't see that post haha, well done!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright I'll be off then! Thanks guys!
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