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anonymous

  • one year ago

Find the inverse of the function. f(x)=3squareroot x/8-4 i keep getting f−1(x)=512x3+6144x2+24576x+32768

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  1. anonymous
    • one year ago
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    when these are the answer choices f-1(x) = [8(x + 4)]3 f-1(x) = 8(x + 4)3 f-1(x) = 8(x3 + 4) f-1(x) = 24(x + 4)

  2. anonymous
    • one year ago
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    Can you draw the function?

  3. anonymous
    • one year ago
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    Because it's not very clear. :)

  4. Jack1
    • one year ago
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    hi... is this your function? \(\Large f(x)=3 \times \sqrt{ \frac x{8-4}}\)

  5. anonymous
    • one year ago
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    no

  6. Jack1
    • one year ago
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    is it this? \(\Large f(x)=3 \times \sqrt{ \frac x8-4}\)

  7. anonymous
    • one year ago
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    \[f(x)=\sqrt[3]{x/8}-4\]

  8. anonymous
    • one year ago
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    Step 1: Change f(x) to y. Step 2: Flip x and y. So y will become x, and x will become y. Step 3: Make the function look like this--> y=mx+b

  9. anonymous
    • one year ago
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    |dw:1439341791162:dw|

  10. anonymous
    • one year ago
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    |dw:1439341863512:dw|

  11. anonymous
    • one year ago
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    Did you understand it or not?

  12. anonymous
    • one year ago
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    After that, make the function look like y=mx+b.

  13. anonymous
    • one year ago
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    so its c?

  14. anonymous
    • one year ago
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    No.

  15. anonymous
    • one year ago
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    how

  16. anonymous
    • one year ago
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    Add 4 on both sides. What will you get?|dw:1439342093820:dw|

  17. anonymous
    • one year ago
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    i was almost positive it was either c or d but now i am very confused

  18. anonymous
    • one year ago
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    lol

  19. anonymous
    • one year ago
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    then can you show me how you did it?

  20. anonymous
    • one year ago
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    what is funny?

  21. anonymous
    • one year ago
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    lol because i'm trying to hep you but it seems like you're saying that my answer is already wrong :D

  22. anonymous
    • one year ago
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    I am not saying that at all I am saying you are right, and i guess i started wrong form the beginning

  23. anonymous
    • one year ago
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    just a quick question: do you know how to add 4 on both sides?

  24. anonymous
    • one year ago
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    nope

  25. anonymous
    • one year ago
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    oh if you don't know, then you can say so. you shouldn't keep people waiting :)

  26. anonymous
    • one year ago
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    sorry

  27. anonymous
    • one year ago
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    do you remember this in algebra 1? |dw:1439342702568:dw|

  28. anonymous
    • one year ago
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    just a quick yes or no is fine

  29. anonymous
    • one year ago
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    no

  30. anonymous
    • one year ago
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    Wait we are both in FLVS Pre-Calculus class right? So basically, you just need to add 4 to x, and the 4 in the right side is now removed. |dw:1439342854963:dw|

  31. anonymous
    • one year ago
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    And then to remove the cube root, you just simply cube it. So from the left side, x+4 will now become \(\huge (x+4)^3\). And the right side will become \(\huge\frac{ y }{ 8 }\).

  32. anonymous
    • one year ago
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    ohhhhh i see

  33. anonymous
    • one year ago
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    The function will now look like this. Now to remove the 1/8 in y/8, simply multiply it by its reciprocal--8--on both sides.. |dw:1439343067959:dw|

  34. anonymous
    • one year ago
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    Multiply 8 on both sides. |dw:1439343171462:dw|

  35. anonymous
    • one year ago
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    From here, what do you think the answer will be? |dw:1439343201548:dw|

  36. Jack1
    • one year ago
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    if i could double medal u i would, awesome explanation @mathway

  37. anonymous
    • one year ago
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    i second Jack! im starting to completely understand!

  38. anonymous
    • one year ago
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    lol i'm flattered

  39. anonymous
    • one year ago
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    i have question though, what is the difference between the brackets and the parentheses?

  40. anonymous
    • one year ago
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    What do you mean? They are just the same, but not totally. I can't explain it.

  41. anonymous
    • one year ago
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    I was asking you a question btw @Abbs__ :D look at the drawing above

  42. anonymous
    • one year ago
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    f-1(x)=8(x+4)3

  43. anonymous
    • one year ago
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    Yes. :)

  44. anonymous
    • one year ago
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    You rock!

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