anonymous
  • anonymous
Find the inverse of the function. f(x)=3squareroot x/8-4 i keep getting f−1(x)=512x3+6144x2+24576x+32768
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
when these are the answer choices f-1(x) = [8(x + 4)]3 f-1(x) = 8(x + 4)3 f-1(x) = 8(x3 + 4) f-1(x) = 24(x + 4)
anonymous
  • anonymous
Can you draw the function?
anonymous
  • anonymous
Because it's not very clear. :)

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Jack1
  • Jack1
hi... is this your function? \(\Large f(x)=3 \times \sqrt{ \frac x{8-4}}\)
anonymous
  • anonymous
no
Jack1
  • Jack1
is it this? \(\Large f(x)=3 \times \sqrt{ \frac x8-4}\)
anonymous
  • anonymous
\[f(x)=\sqrt[3]{x/8}-4\]
anonymous
  • anonymous
Step 1: Change f(x) to y. Step 2: Flip x and y. So y will become x, and x will become y. Step 3: Make the function look like this--> y=mx+b
anonymous
  • anonymous
|dw:1439341791162:dw|
anonymous
  • anonymous
|dw:1439341863512:dw|
anonymous
  • anonymous
Did you understand it or not?
anonymous
  • anonymous
After that, make the function look like y=mx+b.
anonymous
  • anonymous
so its c?
anonymous
  • anonymous
No.
anonymous
  • anonymous
how
anonymous
  • anonymous
Add 4 on both sides. What will you get?|dw:1439342093820:dw|
anonymous
  • anonymous
i was almost positive it was either c or d but now i am very confused
anonymous
  • anonymous
lol
anonymous
  • anonymous
then can you show me how you did it?
anonymous
  • anonymous
what is funny?
anonymous
  • anonymous
lol because i'm trying to hep you but it seems like you're saying that my answer is already wrong :D
anonymous
  • anonymous
I am not saying that at all I am saying you are right, and i guess i started wrong form the beginning
anonymous
  • anonymous
just a quick question: do you know how to add 4 on both sides?
anonymous
  • anonymous
nope
anonymous
  • anonymous
oh if you don't know, then you can say so. you shouldn't keep people waiting :)
anonymous
  • anonymous
sorry
anonymous
  • anonymous
do you remember this in algebra 1? |dw:1439342702568:dw|
anonymous
  • anonymous
just a quick yes or no is fine
anonymous
  • anonymous
no
anonymous
  • anonymous
Wait we are both in FLVS Pre-Calculus class right? So basically, you just need to add 4 to x, and the 4 in the right side is now removed. |dw:1439342854963:dw|
anonymous
  • anonymous
And then to remove the cube root, you just simply cube it. So from the left side, x+4 will now become \(\huge (x+4)^3\). And the right side will become \(\huge\frac{ y }{ 8 }\).
anonymous
  • anonymous
ohhhhh i see
anonymous
  • anonymous
The function will now look like this. Now to remove the 1/8 in y/8, simply multiply it by its reciprocal--8--on both sides.. |dw:1439343067959:dw|
anonymous
  • anonymous
Multiply 8 on both sides. |dw:1439343171462:dw|
anonymous
  • anonymous
From here, what do you think the answer will be? |dw:1439343201548:dw|
Jack1
  • Jack1
if i could double medal u i would, awesome explanation @mathway
anonymous
  • anonymous
i second Jack! im starting to completely understand!
anonymous
  • anonymous
lol i'm flattered
anonymous
  • anonymous
i have question though, what is the difference between the brackets and the parentheses?
anonymous
  • anonymous
What do you mean? They are just the same, but not totally. I can't explain it.
anonymous
  • anonymous
I was asking you a question btw @Abbs__ :D look at the drawing above
anonymous
  • anonymous
f-1(x)=8(x+4)3
anonymous
  • anonymous
Yes. :)
anonymous
  • anonymous
You rock!

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